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3 years ago

Statement

Mathematics

1 answer:

mel-nik [20]3 years ago

8 0

Answer:

True, False, True, True

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A triangle has two constant sides of length 5 feet and 7 feet. The angle between these two sides is increasing at a rate of 0.9

o-na [289]

Answer: $12.74 ft^2/s$

Step-by-step explanation:

Given

Two sides of triangle of sides 5 ft and 7 ft

and angle between them is increasing at a rate of 0.9 radians per second

let $\theta$ is the angle between them thus

Area of triangle when two sides and angle between them is given

$A=\frac{ab\sin C}{2}$

$A=\frac{5\times 7\times \sin \theta }{2}$

Differentiate w.r.t time

$\frac{\mathrm{d} A}{\mathrm{d} t}=\frac{35\cos theta }{2}\times \frac{\mathrm{d} \theta }{\mathrm{d} t}$

at $\theta =\frac{\pi }{5}$

$\frac{\mathrm{d} A}{\mathrm{d} t}=\frac{35\times cos(\frac{\pi }{5})}{2}\times 0.9$

$\frac{\mathrm{d} A}{\mathrm{d} t}=12.74 ft^2/s$

4 0

3 years ago

5×(-2w-4) what's the answer.

maria [59]

Answer:

-10w -20

Step-by-step explanation:

5(-2w-4)

Distribute the 5

5*-2w -5*4

-10w -20

7 0

3 years ago

Read 2 more answers

What is the missing number ?? /6 =25/30

matrenka [14]

Answer:

Step-by-step explanation:

$\frac{25}{30}$ ( divide numerator and denominator by 5 ) , then

$\frac{25}{30}$ = $\frac{5}{6}$ ( with missing number ? = 5 )

8 0

2 years ago

Read 2 more answers

SOMEONE PLEASE HELP ME ON THIS ASAP. I'LL RATE AS BRAINLIEST. PLS PLS PLS PLS

wlad13 [49]

Answer:

I think the answer is city B

Step-by-step explanation:

Hope this helps

4 0

3 years ago

Evelyn and Meredith decided to kayak 1 mile up and then back in the Humboldt channel.

Yakvenalex [24]

The rate of the water flowing in the channel was 2 miles per hour, the rate Evelyn and Meredith were paddling is mathematically given as

v+ = 2.29 1mile/hour

<h3>What is the rate Evelyn and Meredith were paddling?</h3>

Generally, the equation for the up and downstream motion is mathematically given as

vup=v-2

vdown=v+2

Therefore, Statement interpretation

2/3=40*1/60

3+2/3hr=11/3

Where, tup+tdown=11/3

tup+tdown=11/3

1/Vup+1/vdown=11/3

Considering the LCD equation

3(v-2)(V+2)

Hence

$\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}\\\\3(v+2)+3(v-2)=11(v+2)(v-2)$

11v^2-6v-44=0

$v=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Resolving using the equation we have

v+ = 2.29 1mile/hour

v- = -1.745 mile hour