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Mathematics

1 answer:

zysi [14]3 years ago

7 0

Step-by-step explanation:

Pattern 1 :

Arithmetic Sequence

Common term = 4

Pattern 2 :

Geometric Sequence

Common ratio = 2

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Which expression is equivalent to 3(6m) + m? A. 19m B. 21m C. 7m + 3 D. 18m + 6m²

Lelechka [254]

Answer:

3(6m)+m=18m+m=19m so your answer would be A. 19m

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help me with this math problem. I have to Use the quadratic formula to solve each equation.

Ierofanga [76]

You have to solve the given expression for q:

$2q^2-8=3q$

This expression has a quadratic term, which means that it is a quadratic equation. To find the value or values of q, you have to use the quadratic equation, using "q" as the variable instead of "x"

$q=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

a is the coefficient of the quadratic term

b is the coefficient of the q term

c is the constant

- First, zero the equation by passing 3q to the left side of the equal sign:

$\begin{gathered} 2q^2-8=3q \\ 2q^2-8-3q=3q-3q \\ 2q^2-3q-8=0 \end{gathered}$

For this equation the coefficients are:

a= 2

b= -3

c= -8

Replace them in the formula and solve:

$\begin{gathered} q=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ q=\frac{-(-3)\pm\sqrt{(-3)^2-4*2*(-8)}}{2*2} \\ q=\frac{3\pm\sqrt{9+64}}{4} \\ q=\frac{3\pm\sqrt{73}}{4} \end{gathered}$

Next, to determine each possible value of q, you have to solve the sum and difference separately:

Sum