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4 years ago

What is the solution to x=1/2y-3 and y=2x+6

Mathematics

1 answer:

Tom [10]4 years ago

3 0

Answer:

infinite solutions

Step-by-step explanation:

Multiply the first equation by 2 so we don't have fractions.

x = 1/2y - 3 becomes 2x = y - 6

Now substitute the second equation into the y-value of the new equation

2x = (2x + 6) - 6

2x = 2x

x can equal anything. this means there are infinite solutions

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anna has 300naira and ojo has 1860naira.if anna saves 50 naira a day and ojo spends 70 a day, after how many days will they have

ExtremeBDS [4]

Answer:

Anna and Ojo will have same amount after 13 days.

Step-by-step explanation:

Given that:

Anna has 300 naira

She saves 50 naira per day.

Let,

x be the number of days.

y be the amount saved

y = 50x + 300

Ojo has 1860 naira

He spends 70 naira per day.

Let,

x be the number of days

y be the amount left

y = 1860 - 70x

For equal amount, the equations will be equal

50x +300 = 1860 - 70x

50x + 70x = 1860 - 300

120x = 1560

Dividing both sides by 120

$\frac{120x}{120}=\frac{1560}{120}\\x=13$

Hence,

Anna and Ojo will have same amount after 13 days.

4 0

3 years ago

Missy took a math test and got 35 correct and 10 incorrect. What was the percentage of correct answers?(round to the nearest hun

UNO [17]

Answer:

77.77 or 78%

Step-by-step explanation:

She got 35/45 so

35 divided by 45 is 0.777777778

0.777777778 x 100 = 77.7777778

77.77% or 78%

3 0

3 years ago

Different sizes of ribbon need to be cut to go around various shapes for a craft project.

Dima020 [189]

You have five numbers $\sqrt{6},\ 2\dfrac{1}{2},\ -\sqrt{1},\ \dfrac{7}{2}, \ 3.\overline{3}.$

Among them there is one negative number $-\sqrt{1},$ this number is smallest.

Note that

$(\sqrt{6} )^2=6 \text{ and } \left(2\dfrac{1}{2}\right)^2=(2.5)^2=6.25.$

Since 6.25>6, then

$2\dfrac{1}{2}>\sqrt{6}$

and these numbers are less than 3

Note that

$\dfrac{7}{2}=3.5 \text{ and } 3.\overline{3}=3.333333....,$

then $3.3333333...$ and these numbers are greater than 3.

Therefore, the correct order from the smallest to the greatest is:

$-\sqrt{1}, \quad \sqrt{6},\quad 2\dfrac{1}{2},\quad 3.\overline{3}, \quad \dfrac{7}{2}.$

3 0

3 years ago

Given that X={whole numbers less than 24}

hodyreva [135]

Step-by-step explanation:

X= {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23}

P= {2,3,5,7,11,13,17,19,23}

Q= {2,4,6,8,10,12,14,16,18,20,22}

a= {2,3,4,5,6,7,8,10,11,12,13,14,16,17,18,19,20,22,23}

b= {2,}

c= we first find p'

p'={1,4,6,8,9,10,12,14,15,16,18,20,21,22}

c={4,6,8,10,12,14,16,18,20,22}

d=we do same here but we already have p' so we find for q'

q'={1,4,6,8,9,10,12,14,15,16,18,20,21,22}

d={1,4,6,8,9,10,12,14,15,16,18,20,21,22}

6 0

3 years ago

File uploaded. Please help I don't understand this.

Sliva [168]

Answer:

Ms. Brown needs 0.18 more cents to afford the pounds of granola and cranberry mix.

Step-by-step explanation:

Ms. Brown = $10 limit

Purchases 1.75 lbs of granola and 2.9 lbs of cranberry mix

Cranberry per lb = $3.25

Granola per lb = $2.19

1.75 x 2.19 = 3.8325 (Cost of granola)

2.9 x 2.19 = 6.351 (Cost of cranberry)

3.8325 + 6.351 = 10.1835 (Total cost of both cranberry and granola)

10.1835 rounded to nearest cent = 10.18

10 < 10.18

Ms. Brown doesn't have enough money to buy the pounds of granola and cranberry mix.

8 0

3 years ago