Answer:
no
Step-by-step explanation:
if he randomly pulls it out it's still the same number of red cards and also the total number of cards as always
can't change
Answer:
4(2e - 3)(3e + 1)
Step-by-step explanation:
Given
24e² - 28e - 12 ← factor out 4 from each term
= 4(6e² - 7e - 3) ← factor the quadratic
Consider the factors of the product of the e² term and the constant term which sum to give the coefficient of the e- term.
product = 6 × - 3 = - 18 and sum = - 7
The factors are - 9 and + 2
Use these factors to split the e- term
6e² - 9e + 2e - 3 ( factor the first/second and third/fourth terms )
= 3e(2e - 3) + 1 (2e - 3) ← factor out (2e - 3) from each term
= (2e - 3)(3e + 1)
Then
24e² - 28e - 12 = 4(2e - 3)(3e + 1) ← in factored form
The answer would be c because you went left 10 and when you go left its always negative.Then you went down 3 .When going down its also negative
A. This is the original equation: 2x + 3 - 1 = x + 5
b. 2x + 2 = x + 5 ← combined like terms on left side
2x + 2 - 2 = x + 5 - 2 ← used inverse operation to collect constants on right side
2x = x + 3 ←simplified each side
2x - x = x - x + 3 ←used inverse operation to collect variable terms on left side
x = 3 ← simplified each side
answer x = 3
c. 2(3) + 3 - 1 = 3 + 5
6 + 3 - 1 = 8
9 - 1 = 8
8 = 8