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Liula [17]
2 years ago
11

The sixth term of a sequence is 5. The tenth term is 7.

Mathematics
2 answers:
ruslelena [56]2 years ago
5 0
B term= 2x position number -7
worty [1.4K]2 years ago
3 0
<h3>Check the possibilities:</h3><h2>A:</h2>

u(n)=n-1

u(6)=6-1= True

u(10)=10-1≠7 False

<h3>A is eliminated.</h3>

<h2>B:</h2>

u(n)=2n-7

u(6)=2(6)-7=12-7=5 True

u(10)=2(10)-7=20-7≠7 False

<h3>B is eliminated.</h3>

<h2>C:</h2>

u(n)=0.5n+2

u(6)=0.5(6)+2=3+2=5 True

u(10)=0.5(10)+2=5+2=7 True

<h2>C is your answer.</h2>

<h3>Check D although we know it's C:</h3>

u(n)=n/6 +4

u(6)=6/6 +4=1+4=5 True

u(10)=10/6 +4=2.5+4=6.5≠7 False

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Juan pulled a red card from the deck of regular playing cards. This probability is 2652 or 12 . He puts the card back into the d
kenny6666 [7]

Answer:

no

Step-by-step explanation:

if he randomly pulls it out it's still the same number of red cards and also the total number of cards as always

can't change

6 0
3 years ago
Read 2 more answers
Factorise 24e^2-28e-12
Helga [31]

Answer:

4(2e - 3)(3e + 1)

Step-by-step explanation:

Given

24e² - 28e - 12 ← factor out 4 from each term

= 4(6e² - 7e - 3) ← factor the quadratic

Consider the factors of the product of the e² term and the constant term which sum to give the coefficient of the e- term.

product = 6 × - 3 = - 18 and sum = - 7

The factors are - 9 and + 2

Use these factors to split the e- term

6e² - 9e + 2e - 3 ( factor the first/second and third/fourth terms )

= 3e(2e - 3) + 1 (2e - 3) ← factor out (2e - 3) from each term

= (2e - 3)(3e + 1)

Then

24e² - 28e - 12 = 4(2e - 3)(3e + 1) ← in factored form

8 0
3 years ago
Which rule describes the transformation that was used to form parallelogram A'B'C'D'
Ainat [17]
The answer would be c because you went left 10 and when you go left its always negative.Then you went down 3 .When going down its also negative

3 0
3 years ago
X discounted 30% is 42. What is x?
9966 [12]
X would end up being 80
6 0
3 years ago
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Can someone please help me solve this?
Akimi4 [234]
A. This is the original equation: 2x + 3 - 1 = x + 5

b. 2x + 2 = x + 5 ← combined like terms on left side 
    2x + 2 - 2 = x + 5 - 2 ← used inverse operation to collect constants on right side
    2x = x + 3 ←simplified each side
    2x - x = x - x + 3 ←used inverse operation to collect variable terms on left side
    x = 3 ← simplified each side 
answer x = 3

c. 2(3) + 3 - 1 = 3 + 5
     6 + 3 - 1 = 8
       9  - 1 = 8
        8 = 8 
4 0
3 years ago
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