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san4es73 [151]
3 years ago
14

Given that lines a and bare parallel, what angles formed on line b when cut by the transversal are congruent with <3

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0

Alternate Interior Angles forms when two parallel lines cut by transversal.

Step-by-step explanation:

Transversal is a line that intersects two or more lines.

Alternate Interior Angles forms when two lines are cut by a Transversal, the pairs of angles on either side of the transversal and inside the two lines.

Take 8 angles, 1,2,3,4,5,6,7 & 8 present on the lines A & B. Let C is a transversal cutting the lines A & B.

Here the pairs of angles are 1 & 5, 2 & 6, 3 & 7, 4 & 8.

Alternate Interior angles are 3 & 5, 4 & 6.

If two parallel lines are cut by a transversal, then the alternate interior angles should form congruent.

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An urn contains a very large number of marbles of four different colors: red, orange, yellow, and green. A sample of 12 marbles d
Umnica [9.8K]

Answer:

We  can reject the hypothesis at the 0.05 significance level.

 

Step-by-step explanation:

given that an urn contains  a very large number of marbles of four different colors: red, orange, yellow, and green. A sample of 12 marbles drawn at random from the urn revealed 2 red, 5 orange, 4 yellow, and 1 green marble.

H0: All colours are equally likely

Ha: atleast two colours are not equally likely

(Two tailed chi square test at 5% significance level)

color                  Red           Orange      Yellow      Green         total

Observed  O         2                     5                  4           1              12    

Expected   E         3                     3                   3          3              12

(O-E)^2/E             0.3333            5.3333        0.3333  5.3333     11.3333

chi square = 11.3333

df =3

p value = 0.010055

Since p < 0.05 we reject H0

We  can reject the hypothesis at the 0.05 significance level.

 

3 0
3 years ago
If a=-2 and b = 3, what is the value of -3a2b?
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birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia
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Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of  lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

z_1 = \dfrac{X-\mu}{\sigma}

-1.88 = \dfrac{X-3570}{500}

By cross multiply, we have:

-1.88 × 500 = X - 3570

-940 = X - 3570

-X = -3570 + 940

-X = -2630

X = 2630 g

Hence, 2630 g is the required weight of birth   that differentiates the babies that needed special treatment from those that do not

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