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Anit [1.1K]
3 years ago
14

Look at picture. Tell me what G(x)=?

Mathematics
2 answers:
kari74 [83]3 years ago
8 0
The answer is 3 :) hope helps
Misha Larkins [42]3 years ago
5 0
Attached solution and work.

You might be interested in
Find the height of a trapezoid if the bases have lengths of 6 and 17 and the area of the trapezoid is 46 square units.
Aleksandr [31]

Answer:

4 units

Step-by-step explanation:

The area (A) of a trapezoid is calculated using the formula

A = \frac{1}{2} h(a + b)

where h is the height and a, b the bases

here A = 46, a = 6 and b = 17, hence

46 = \frac{1}{2} h(6 + 17) ( multiply both sides by 2 )

92 = h(23) ← divide both sides by 23 )

h = \frac{92}{23} = 4 units

8 0
3 years ago
Find the area of a regular octagon with a side length of 4 cm.​
goblinko [34]

Answer:

77.25 cm^2

Step-by-step explanation:

Area of a regular octagon :

2a^2(1 + (sqrt2))

where a is the side

substitute 4 in for 'a'

6 0
3 years ago
Giving brainliest and max rating.
Yanka [14]

Given:

The cost of each carnival ticket is $5.

To find:

The equation, table of values and graph for the given problem.

Solution:

Let x be the number of tickets and y be the total money spent on tickets.

Cost of one ticket = $5

Cost of x tickets = $5x

So, total cost is

y=5x

The required equation is y=5x.

At x=1,

y=5(1)

y=5

At x=2,

y=5(2)

y=10

At x=3,

y=5(3)

y=15

The required table of values is

x       y

1        5

2      10

3      15

So, the required table of values is table A.

From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.

So, the required graph is graph B.

Since the required answers are y=5x, table A, graph B, therefore the correct option is B.

8 0
3 years ago
Someone please help me out:(
gogolik [260]
SAS mmmmmmmmmmmmmmmmmmm
5 0
3 years ago
A circle has a circumference of 3.14<br> What is the diameter of the circle?
Sonbull [250]
3.82 is the answer for that but what is the unit of measurement

4 0
3 years ago
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