Given:
Amanda sold 13 rolls of plain wrapping paper and 12 rolls of holiday wrapping paper for a total of $208.
And,
Mofor sold 4 rolls of plain wrapping paper and 3 rolls of holiday wrapping paper for a total of $55.
Let, x be the cost of one roll of plain wrapping paper and y be the cost of one roll of holiday wrapping paper.
The equations are,
![\begin{gathered} 13x+12y=208\ldots\ldots\ldots\text{.....}(1) \\ 4x+3y=55\ldots\ldots..\ldots\ldots\ldots\text{.}(2) \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2013x%2B12y%3D208%5Cldots%5Cldots%5Cldots%5Ctext%7B.....%7D%281%29%20%5C%5C%204x%2B3y%3D55%5Cldots%5Cldots..%5Cldots%5Cldots%5Cldots%5Ctext%7B.%7D%282%29%20%5Cend%7Bgathered%7D)
Solve the equations,
![\begin{gathered} 4x+3y=55 \\ 4x=55-3y \\ x=\frac{55-3y}{4} \\ \text{Put it in quation (1)} \\ 13x+12y=208 \\ 13(\frac{55-3y}{4})+12y=208 \\ \frac{715-39y}{4}+12y=208 \\ 715-39y+4(12y)=4(208) \\ 715-39y+48y=832 \\ 9y=832-715 \\ 9y=117 \\ y=\frac{117}{9} \\ y=13 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%204x%2B3y%3D55%20%5C%5C%204x%3D55-3y%20%5C%5C%20x%3D%5Cfrac%7B55-3y%7D%7B4%7D%20%5C%5C%20%5Ctext%7BPut%20it%20in%20quation%20%281%29%7D%20%5C%5C%2013x%2B12y%3D208%20%5C%5C%2013%28%5Cfrac%7B55-3y%7D%7B4%7D%29%2B12y%3D208%20%5C%5C%20%5Cfrac%7B715-39y%7D%7B4%7D%2B12y%3D208%20%5C%5C%20715-39y%2B4%2812y%29%3D4%28208%29%20%5C%5C%20715-39y%2B48y%3D832%20%5C%5C%209y%3D832-715%20%5C%5C%209y%3D117%20%5C%5C%20y%3D%5Cfrac%7B117%7D%7B9%7D%20%5C%5C%20y%3D13%20%5Cend%7Bgathered%7D)
Put the value of y in equation (2),
![\begin{gathered} 4x+3y=55 \\ 4x+3(13)=55 \\ 4x+39=55 \\ 4x=55-39 \\ 4x=16 \\ x=\frac{16}{4} \\ x=4 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%204x%2B3y%3D55%20%5C%5C%204x%2B3%2813%29%3D55%20%5C%5C%204x%2B39%3D55%20%5C%5C%204x%3D55-39%20%5C%5C%204x%3D16%20%5C%5C%20x%3D%5Cfrac%7B16%7D%7B4%7D%20%5C%5C%20x%3D4%20%5Cend%7Bgathered%7D)
Answer:
The cost of one roll of plain wrapping paper is x = $4.
The cost of one roll of holiday wrapping paper is y = $13.
Answer:
8000
Step-by-step explanation:
Let the required number be x.
![\therefore \: \frac{3}{8} \% \: of \: x = 30 \\ \\ \therefore \: \frac{3}{800} \times x = 30 \\ \\ \therefore \: x = 30 \times \frac{800}{3} \\ \\ \therefore \: x = 10 \times 800 \\ \\ \therefore \: x = 8000 \\](https://tex.z-dn.net/?f=%20%5Ctherefore%20%5C%3A%20%20%5Cfrac%7B3%7D%7B8%7D%20%20%5C%25%20%5C%3A%20of%20%5C%3A%20x%20%3D%2030%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%20%20%5Cfrac%7B3%7D%7B800%7D%20%20%5Ctimes%20x%20%3D%2030%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%20x%20%3D%2030%20%5Ctimes%20%20%5Cfrac%7B800%7D%7B3%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%20x%20%3D%2010%20%5Ctimes%20800%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%20x%20%3D%208000%20%5C%5C%20)
The answer to this is .15%
Answer:
108
Step-by-step explanation:
Since angle AFB and angle BFC are next to each other and form a straight line, we can subtract 72 from 180 to get the missing angle measurement. (all straight lines add up to 180)
180-72=108
So 108 would be your answer
Answer:
x = 6
Step-by-step explanation:
x = 3 is the equation of a vertical line parallel to the y- axis.
The equation of a parallel line will therefore be a vertical line.
The equation of a vertical line is
x = c
where c is the value of the x- coordinates the line passes through.
The line passes through (6, 1) with x- coordinate 6, thus
x = 6 ← equation of parallel line