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otez555 [7]
3 years ago
12

If M = 624,619,430,000 find the smallest power of 10 that will exceed M

Mathematics
1 answer:
AveGali [126]3 years ago
8 0

<u>Answer-</u>

<em>The smallest power of 10 that will exceed M is 12.</em>

<u>Solution- </u>

Here,

M = 624,619,430,000

Writing this number in scientific notation,

M = 624,619,430,000 = 6.24619430\times 10^{11}

As the given number is the order of 11, so the next order will be greater than M.

So the next order of 10 will be,

=10^{11+1}

=10^{12}

Therefore, the smallest power of 10 that will exceed M is 12.

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Step-by-step explanation:

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459,450,441,..

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Putting n=38 to find the 38th term

a_n=-9n+468

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Therefore, the 38th term of 459,450,441,.. will be:

a_{13}=351

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Answer:

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