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3 years ago

Value 10. 5 + 3 times 2 minus 6

Mathematics

1 answer:

krok68 [10]3 years ago

8 0

10.5 + 3 X 2 - 6 = 10.5

steps: 3X2 = 6

10.5 + 6 = 16.5

16.5- 6 = 10.5

let me know if i did something wrong

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What is 144.8 divided by 4

vredina [299]

Answer:

36.2

Step-by-step explanation:

144.8/4 = 36.2

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3 years ago

Read 2 more answers

−126 = 14k<br> MAKE SURE TO SHOW YOUR WORK PLEASE HURRY

vovangra [49]

Answer:

k = -9

Step-by-step explanation:

When a number (coefficient) is next to a letter (variable) that means you multiply. To solve you would to the opposite, which is to divide.

-126 ÷ 14 = -9

So -9 is equal to k.

Hope that helps and have a great day!

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4 years ago

Find the slope of the line that passes through (10, 2) and (1, 6).

hjlf

The original answer would be 4 over negative 9 but when divide a positive by a negative your new answer would be negative 4 over 9. The correct format should be negative 4 over 9

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3 years ago

Find the deriative dy/dx for y=x^2-2x/x^3+3

vaieri [72.5K]

Answer:

$\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})$

Step-by-step explanation:

So we want to find the derivative of the rational equation:

$y=\frac{x^2-2x}{x^3+3}$

First, recall the quotient rule:

$(\frac{f}{g})'=\frac{f'g-fg'}{g^2}$

Let f be x^2-2x and let g be x^3+3.

Calculate the derivatives of each:

$f=x^2-2x\\f'=2x-2$

$g=x^3+3\\g=3x^2$

So:

$\frac{dy}{dx}=(\frac{x^2-2x}{x^3+3})'$

Use the above format:

$\frac{dy}{dx}=\frac{f'g-fg'}{g^2}\\\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})$

And that's our answer :)

(If you want to, you can also expand. However, no terms will be canceled.)

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3 years ago

Is the polynomial t^4-7 in standard form?

VMariaS [17]

Answer:

The polynomial $t^4-7$ is in standard form.

Step-by-step explanation:

Writing the polynomial in standard form means we have to write the terms of the polynomial by descending degree.

First writing the term with the highest or largest exponent or degree first

Then writing the terms which have lower degrees/exponents in descending order.

If there is any constant term in the polynomial, it is always written in the end.

Given the polynomial

$t^4-7$

Here:

The highest exponent is the 4, so that entire term i.e. $t^4$ is written first. Here it is also written first.

Then the next term is the constant term, and constant terms is written in the end. Here, the constant terms is also written in the end.

Therefore, the polynomial $t^4-7$ is in standard form.

5 0

3 years ago