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Yakvenalex [24]
4 years ago
8

Write an equation for the line perpendicular to y = 5x – 12 that contains (–3, –1).

Mathematics
2 answers:
elixir [45]4 years ago
6 0
The answer is B

<span>Write an equation for the line perpendicular to y = 5x – 12 
that contains (–3, –1).
----------------
The given equation has slope = 5
----
The desired equation must have slope = -1/5
-------
Form: y = mx + b
Solve for "b" when m = -1/5 and y = -1 when x = -3

==================
-1 = (-1/5)(-3) + b
-1 = (3/5) + b
b = -8/5
------------------
Answer=</span><span>y + 1 = 5(x + 3)</span>
Fed [463]4 years ago
5 0
Y = 5x - 12
Here, slope = 5
Perpendicular line slope = -1/5  [ opposite and reciprocal ]

Now, y - y1 = m(x - x1)
y + 1 = -1/5 (x + 3)

In short, Your Answer would be Option B

Hope this helps!
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                   = 207.5385/26−1   ≈ 8.3015

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