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3 years ago

Answer this! I WILL GIVE BRAINLIEST TO PERSON WHO GIVES CORRECT ANSWER!!!!!!!!!

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

An 18-month loan with a 4.75% annual simple interest rate

Step-by-step explanation:

have a good day/night

may i please have a branlliest

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WILL GIVE BRAINLIEST!!!!!

ruslelena [56]

Answer:

Step-by-step explanation:

m∠BCD = 145° ⇒ m∠BCA = 180° - 145° = 35°

From ΔABC:

m∠ABC + m∠BCA + m∠BAC = 180°

65° + 35° + m∠BAC = 180°

m∠BAC = 180° - 100°

m∠BAC = 80°

5 0

3 years ago

What is the m∠ACB in the circle shown below?

GuDViN [60]

Question:

What is the m∠ACB in the circle shown below?

Answer:

Step-by-step explanation:

So we know it is <u><em>less than a right angle</em></u> and it is not a obtuse angle it is less than 90 degrees. 45 is less, 90 is equal(<em>not what we are looking for</em>) , 120, is greater, and 180 is greater which leaves us to our answer 45.

4 0

3 years ago

After the 4th half life how much of the sample is left if the mass is 100g.

vazorg [7]

Answer:

$\huge\boxed{\sf 6.25 \ g}$

Step-by-step explanation:

After every Half life , Half of the mass is left.

After 1st Half life = 100 g / 2 = 50 g

After 2nd Half life = 50 / 2 = 25 g

After 3rd Half life = 25 / 2 = 12.5 g

After 4th Half life = 12.5 / 2 = 6.25 g

$\rule[225]{225}{2}$

Hope this helped!

6 0

3 years ago

Express this equation in logarithmic form. y = 10^x<br><br> x = ?

Lana71 [14]

From definition we have:

$$x=\log_{10}y$

8 0

3 years ago

Genius question: A long level railway bridge passes over a railroad track, which is 100 feet below it and at right angles to it.

nataly862011 [7]

Answer: <u>110 feet per second</u>

Step-by-step explanation:

In this problem we will assume that the car at 45 miles per hour is moving into the x direction with a high of 100 feet, and the train is going in the y direction, so they trajectories will made an angle of 90º.

Now we can calculate the speed of the trains in feet per second so:

$S1=\frac{45*5280}{3600}=66$

$S2=\frac{60*5280}{3600}=88$

So we can make a right triangle with sides 66 and 88 and the hypotenuse will be the rate that the trains will separate per second so:

$h=\sqrt{66^{2} +88^{2} } =\sqrt{4356+7744}$

$h=\sqrt{12100}=110$

Is important to have in mind that the initial high is not going to change how fast the trains will separate, however, if we are going to calculate the distance we should have it in the calculations.

7 0

3 years ago