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vlada-n [284]
3 years ago
14

40 POINTS, please help

Mathematics
1 answer:
Elis [28]3 years ago
8 0

First, we must understand what standard form of a line is. Standard form of a line is written like  such that A,B, and C are all integers, and A must be positive. First, we must calculate the slope of the line that passes through theses coordinates. 

 

<span>As a refresher, this is the equation to figure out the slope of two coordinates.Now, we just simplify the numerator and denominator.  <span>  </span></span>

 

The next step is to utilize point-slope form, which is  where  is a point on the line. Of course, we already know that (7,-3) and (4,-8) both lie of the line. Therefore, plug in one fot he coordinates. Once converted into point-slope, we must then convert into standard form. This is what is demonstrated in the next step. 

 

<span>Let's multiply all sides by 3 to get rid of the fraction early.Distribute the 5 to both terms in the parentheses.Subtract 9 from both sides.Subtract 5x on both sides.We aren't done yet! The coefficient of the x-term must be positive. Therefore, divide by -1 on both sides.<span>This is standard form now, so we are done!</span></span>
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If sin y° = 7 over q and tan y° = 7 over r, what is the value of sec y°?
Tomtit [17]

Answer:

Sec y = q/r

Step-by-step explanation:

Sin y = 7/q

tan y = 7/r

Mathematically cos y = sin y/tan y

But sec y = 1/cos y

So therefore sec y = tan y/sin y

So that would be ;

7/r divided by 7/q

= 7/r * q/7

= q/r

3 0
3 years ago
Write the equation of the line through (6,4) that is parallel to the line whose equation is y= 1/2 x+7. Show all work below and
soldier1979 [14.2K]

Answer:

\displaystyle y = \frac{1}{2}x + 1

Step-by-step explanation:

4 = ½[6] + b

3

\displaystyle 1 = b \\ \\ y = \frac{1}{2}x + 1

I am joyous to assist you anytime.

5 0
3 years ago
Does anyone know what goes into these blanks
avanturin [10]

yes I know but will not give answer because you have not say that

4 0
3 years ago
Doug, a student in this class, knows how to write programs in JAVA. Everyone who knows how to write programs in JAVA can get a h
In-s [12.5K]

Missing Part of Question

Explain which rules of inference are used in the above

Answer:

Universal instantiation, Modus ponens and Existential generalization

Step-by-step explanation:

Splitting the Statement into two, we have

"Doug knows how to write program is Java"

and

"Doug can get a high paying job"

Represent Doug with x. Then the statements is rewritten as

P(x) = "x knows how to write program is Java"

and

Q(x) = "x can get a high paying job"

In logic, A premise is a statement in an argument that provides reason or support for the conclusion.

So, Statement 1 can be written as

1. P(x) ---- Premise

Then, we have

2. Vx(P(x) --> Q(x)) -- Premise. This mean that P(x) for all values in the domain.

The universal instantiation of (2) leads to

3. P(Doug) --> Q(Doug)

The modus ponens of the above gives

4. Q(Doug)

The existential generalisation from above gives

5. ƎxQ(x)

Which means someone in this class can get a high paying job.

PS:

Universal Instantiation is a valid rule of inference from a truth about each member of a class of individuals to the truth about a particular individual of that class; it is represented by VxP(x).

Existential Generalisation is a valid rule of inference that allows one to move from a specific statement, or one instance, to a quantified generalized statement, or existential proposition.

It is represented as ƎxP(x)

4 0
3 years ago
How to evaluate the expression
jasenka [17]

Answer:

1

Step-by-step explanation:

4^{5} can be expressed as 2^{(2)(5)} = 2^{10}

Similarly 4^{8} can be expressed as 2^{(2)(8)} = 2^{16}

Numerator becomes:

2^{10} · -2^{9} = -2^{19}

Denominator becomes:

2^{16} · -2^{3} = -2^{19}

Since numerator = Denominator,

Answer = 1

Edit reason: typo

4 0
3 years ago
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