Answer:
x=2
TU:4(2)-1=7
UB: 3
TB: 10
Step-by-step explanation:
4x-1+2x-1=5x
6x-2=5x
6x=5x+2
subtract 5x from both sides
x=2
TU: (4x-1)
4(2)-1
8-1
7
TU:4(2)-1=7
UB: (2x-1)
2(2)-1
4-1
3
UB: 3
TB: 5(2)
TB: 10
Answer:
Step-by-step explanation:
Given that there are three variables satisfying the equation

Here each x is given to be a positive integer
i.e. solution set for each of the variable can be any integer from 1 to 20 at most.(because if two other integers are 1 each third has to be 20)
Hence solution set can be of the form


If x1 =1, there are 20 solution sets
If x1 =2,there are 19
...
If x1 =20 there is 1 set
Hence total solutions can be