An office room is 12 ft by 10 ft with a door that is 30 inches wide. How many feet of baseboard are needed to go around the room
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Thank you so much :)
Thank you so much :)
1 answer:
Draw a diagram to illustrate the problem as shown below.
The length of baseboard needed is AB + BC + CD + DE + FE.
Note that 30 in = 30/12 ft = 2.5 ft.
Because of the door opening,
AB + EF = 12 - 2.5 = 9.5 ft
Also,
BC = DE = 10 ft
CD = 12 ft.
The amount of baseboard needed is
AB + BC + CD + DE + FE
= (AB + EF) + BC + CD + DE
= 9.5 + 10 + 12 + 10
= 41.5 ft
Answer:
41.5 feet of baseboard.
The length of baseboard needed is AB + BC + CD + DE + FE.
Note that 30 in = 30/12 ft = 2.5 ft.
Because of the door opening,
AB + EF = 12 - 2.5 = 9.5 ft
Also,
BC = DE = 10 ft
CD = 12 ft.
The amount of baseboard needed is
AB + BC + CD + DE + FE
= (AB + EF) + BC + CD + DE
= 9.5 + 10 + 12 + 10
= 41.5 ft
Answer:
41.5 feet of baseboard.
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Answer:
Given : BRDG is a kite that is inscribed in a circle,
With BR = RD and BG = DG
To prove : RG is a diameter
Proof:
Since, RG is the major diagonal of the kite BRDG,
By the property of kite,
∠ RBG = ∠ RDG
Also, BRDG is a cyclic quadrilateral,
Therefore, By the property of cyclic quadrilateral,
∠ RBG + ∠ RDG = 180°
⇒ ∠ RBG + ∠ RBG = 180°
⇒ 2∠ RBG = 180°
⇒ ∠ RBG = 90°
⇒ ∠ RDG = 90°
Since, Angle subtended by a diameter or semicircle on any point of circle is right angle.
⇒ RG is the diameter of the circle.
Hence, proved.
