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amid [387]
3 years ago
13

Two stores have movies to rent

Mathematics
2 answers:
Nesterboy [21]3 years ago
7 0

Answer:7

Step-by-step explanation:

In the first store, you pay 12.5+1.5x per x movies

In the second store, you pay 3.5x per x movies

The first store offers a better deal when:

12.5 + 1.5x > 3.5x

12.5 > 2x

6.25 > x

Which means if you rent minimum 7 movies in month, you should go to the first store

gtnhenbr [62]3 years ago
5 0

Answer:

<h2>7</h2>

Step-by-step explanation:

We know that the first store charges $12.50 per month, which is a initial condition, and charges additionally $1.50 per movie, which is variable, this represents the ratio of change, so this can be expressed as

\$12.50 + \$1.50x

Where x represents movies.

Now, the second store doesn't charge and membership fee, just it charges a cost per movie which is $3.50.

Then, to solve the minimum number of movies needed to Plan A be the best choice, we just have to solve the following inequality

\$12.50 + \$1.50x> \$3.50

Which expresses the case where Plan A is a better choice, solving for x, we have

\$12.50 + \$1.50x> \$3.50x\\\$1.50x - \$3.50x >-\$12.50\\(-1)(-2x)>(-12.50)(-1)\\2x

Which means that the minimum number of movies is 7, which is the next whole number after 6.

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Hey there, Dudedan!
In a#b = a+2b, we have the first term, a, plus 2 times the second term, b.
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