Since we are given the values for both rows only in the second column, we can use this to solve for the rest of the missing values. Simply divide 3 by 2.49 and multiply that resultant by and multiply that by any missing value for cookies to find the missing cost. In order to solve for the cookies when cost is given, divide 2.49 by 3 and multiply that resultant. I will solve for the first, third, and fourth columns.
3/29=1.2
For column 1, 1.2*1=1.20
For column 3, 1.2*20=24.10
For column 4, 1.2*100=12.00
I would go with B i had this question on my test and i got it correct
Answer:
1. X is added to 8
2. Subtract 14 by a number
3. Multiply 2 after you add 3 into a number.
4.. Twice a number plus 3
5. Divide 15 by a number
Step-by-step explanation:
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
BPD = 1/2(BD + CA)
BPD = 1/2(70 + 170)
BPD = 1/2(240)
BPD = 120
A full circle = 360 degrees
BC + AD = 360 - 70 - 170
BC+ AD = 360 - 240
BC + AD = 120
