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bagirrra123 [75]
3 years ago
12

Using the picture solve for the answer

Mathematics
1 answer:
iren [92.7K]3 years ago
6 0

Answer:

i love you :)

Step-by-step explanation:

B only

cos B = a/c

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Artist 52 [7]

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Can you help me out ​
Advocard [28]
The answer is 20

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2 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
List 3 values that would make this inequality true 48 < 6n​
icang [17]

Answer:

Step-by-step explanation:

Turn the question around so it is easier to see.The open end is closest to n.

6n>48          Divide by 6

6n/6>48/6

n > 8

So all you have to do is choose 3 values greater than 8

How about 9,10,11

4 0
3 years ago
Consider the line through (-1, -4) and (1, 2).<br>  What is the slope (m) of the line?<br>​
zloy xaker [14]

Answer:

<u><em>3</em></u>

Explanation:

  • \bold{\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}}

\bold{\left(x_1,\:y_1\right)=\left(-1,\:-4\right),\:\left(x_2,\:y_2\right)=\left(1,\:2\right)}

\bold{m=\frac{2-\left(-4\right)}{1-\left(-1\right)}}

  • Refine

<u><em>m = 3</em></u>

5 0
3 years ago
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