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3 years ago

Using the picture solve for the answer

Mathematics

1 answer:

iren [92.7K]3 years ago

6 0

Answer:

i love you :)

Step-by-step explanation:

B only

cos B = a/c

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Eric and Mark were at a ball game and visited the concession stand. They each got a hamburger, and Mark got lemonade and some co

EastWind [94]

So here is the answer. Given that both Eric and Mark got a hamburger which is $4 each. Mark got a lemonade and some cotton candy which costs $5.
So this gives them a total of $4, $4, $5, $?(lemonade). Partial sum is $13 without the lemonade. Since Eric got a $2, the total bill was deducted with $2 and the rest of the amount is $14.50. Therefore, the total bill would have been $16.50. So $16.50 minus $13 (partial sum) is $3.50. So the lemonade costs $3.50. Hope this helps.

3 0

3 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago

Help me please (no links please)

stich3 [128]

a) This part is already complete I think..

b) This is a cuboid and lateral surface area of cuboid is: 2(lb +bh + hl)

= 2( 10 × 3 + 3 × 7 + 7 × 10)

= 2(30 + 21 + 70)

= 2 × 121 = 242 cm²

Now, the area of top & bottom: lb

= 2 × 10 × 3

= 60 cm²

Neglecting the top & bottom surface area of cuboid:

= 242 - 60

= 180 cm²

c) The total surface area us 242.. I have already done that part above...

__________________________

If i have done something wrong.. please lemme know :)

7 0

2 years ago

If five times the measure of an angle is decreased by 30, the result is the same as when two times the measure of the angle is i

Serhud [2]

Answer:

Step-by-step explanation:

Let "a" represent the measure of the angle. Then ...

5a -30 = 2a +18

3a = 48 . . . . . . . add 30-2a

a = 16 . . . . . . . . . divide by 3

An angel is beyond measure, but this angle has measure 16.

4 0

3 years ago

(5x +<br> 12)<br> 48°<br> solve for x.

zimovet [89]

Answer: It is 108

Step-by-step explanation:

7 0

3 years ago