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3 years ago

Simplify the following using scientific notation (8.76×109)(6.52×10-³)/13.27×105

Mathematics

1 answer:

OLEGan [10]3 years ago

6 0

8.76 * 10^9 * 6.52 * 10^-3

= 57.1152 * 10^6

57.1152 * 10^6 / 13.27 * 10^5

= 4.30408 * 10^1 which can be written as 43.0408 ( correct to 4 dp's)

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Can anyone help please right answer only

BARSIC [14]

The value of x is 27°.

Solution:

Given $\triangle \mathrm{ACB} \cong \Delta \mathrm{DCE}$ .

∠A = 3x – 10, ∠C = 45°, ∠D = 2x + 10

<em>If two triangles are congruent, then the angles are congruent.</em>

∠A = ∠E (Alternate interior angles)

∠C = ∠C (Reflexive property)

∠B = ∠D (Alternative interior angles)

⇒ ∠B = 2x + 10

<em>Sum of the interior angles of the triangle = 180°</em>

In ΔACB,

3x – 10 + 45° + 2x + 10 = 180°

5x + 45° = 180°

Subtract 45° on both sides of the equation.

5x = 135°

Divide by 5 on both sides of the equation.

x = 27°

The value of x is 27°.

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3 years ago

Math help What are the solutions

Westkost [7]

Answer:

x² - 4x + 12

Step-by-step explanation:

x=2+2.82843i

x=2−2.82843i

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3 years ago

At the restaurant, your family orders a subtotal of $46.55. Add 6% sales tax and 18% tip. What is the total?

ICE Princess25 [194]

Answer:

Step-by-step explanation:

Now,

if you add the tip after the sales tax,

you will have:

46.55*(6/100)=2.79

the meal cost now 46.55+2.79=49.34

we add tip

49.34*(18/100)=8.88

total cost 49.34+8.88=58.22

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3 years ago

True or False

3241004551 [841]

True the circle is a congruent to the radius of an inscribed regular polygon inside the circle

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3 years ago

Read 2 more answers

List all possible rational roots. Then use synthetic division to confirm which rational roots exist:

Kisachek [45]

Answer:

$\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}$

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.

$\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}$

In your function, the constant term is -10 and the leading coefficient is 2, so

$\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}$

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

$\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}$

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

$\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}$

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0

3 years ago