I=prt,,i=575*0.055*2,,i=63.25 total interest then A=p+i,,a=575+63.25,,A=638.25 the answer
Answer:
x ≈ 4.8
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] cos∅ = adjacent over hypotenuse
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle measure = 58°
Adjacent side of angle = <em>x</em>
Hypotenuse = 9
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [cosine]: cos58° = x/9
- Isolate <em>x</em>: 9cos58° = x
- Evaluate: 4.76927 = x
- Rewrite: x = 4.76927
- Round: x ≈ 4.8
The answer to that will be the letter c , 24ft
The answer is 5.
Step-by-step explanation:
To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.
Answer:
225 frogs
Step-by-step explanation:
Total population of frogs = 300 frogs.
Observed population of frogs = 24
6 of the 24 observed frogs had spots
Which means , the number of frogs that did not have spots = 24 - 6 = 18 frogs.
We were told to find how many of the total population can be predicted to NOT have spots. We would form a proportion.
If 24 frogs = 18 frogs with no spots
300 frogs = Y
Cross multiply
24Y = 300 × 18
Y = (300 × 18) ÷ 24
Y = 5400 ÷ 24
Y = 225 frogs.
This means out of 300 frogs, 225 frogs do not have spots.
Therefore, the total population that can be predicted to NOT have spots is 225 frogs.
the total population can be predicted to NOT have spots
