All categories

2 years ago

What can 12 and 7 go into

Mathematics

2 answers:

grandymaker [24]2 years ago

5 0

The only possibility would be 1

ivolga24 [154]2 years ago

3 0

12 can go into 24,36,48,60 to name a few
7 can go in to 14, 21, 28.

look at the times tables. anything times a number , that number can go into. like 4x5 = 20. 20 can go into 4 and 5

You might be interested in

Choose the correct description of the graph of the compound inequality x − 1 less than or equal to 9 or 2x greater than or equal

DerKrebs [107]

X - 1 < = 9 or 2x > = 24
x < = 9 + 1 x > = 24/2
x < = 10 x > = 12

closed circle on 10, shaded to the left
closed circle on 12, shaded to the right

________10_______12__________
<====X X======>
the X represents closed circles

8 0

2 years ago

Express 7/8 as a decimal

Mekhanik [1.2K]

$\displaystyle \frac{7}{8} = \frac{7 \times 125}{8 \times 125} \\\\ = \frac{875}{1.000} \rightarrow \boxed{\boxed{0,875}}$

6 0

2 years ago

Write 6.3 x 10^4 in standard notation.

icang [17]

The power of 4 means to move the decimal 4 places to the right. 6.3 x 10^4
63000

6 0

2 years ago

Read 2 more answers

Which expression shows the correct way to find the distance between<br> (23,17) and (43,14)? ( TTM)

Lesechka [4]

Answer:

d= $\sqrt{x} (43-23)^2+(14-17)^2$

Answer= 20.224

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Sample Size for Proportion As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of gol

Dima020 [189]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

6 0

3 years ago