To find the volume of a box that would hold these nine cylinders, you would start with the formula for volume of a cylinder. V=pi x r^2 x h. Substitute in the known volume and the known Height. 9.425=pi x r^2 x 3. Divide both sides by three to get approximately 3.143 = pi x r^2. Divided by pi on both sides. This leaves you with one = r^2. So the radius is equal to one. If the radius equals one, the diameter is two. Assuming the cylinders are arranged in a 3 x 3 array, the length and width of the rectangle or box would be 6cm x 6cm. To find the volume of the box necessary, multiply the length of six by the width of six by the height of three. The volume would be 108 square cm.
Should be the first option.
Since ABP is congruent to CBP in the 4th step, AP must be equal to CP
Well, if any number is higher than '5' it turns one number more. So, here's a good rhyme to help you: "Five or more, up the score, Four or less, let it rest." The maximum number it could be would have to be '444' because it is not bigger than 445, which would turn to 500.
Since the sine and cosine functions are cofunctions, they are complementary. The format for this is that sinx=cos(90-x). This works for secant and cosecant and tangent and cotangent. So, sin25°=cos65°.
Answer:
i believe 1 is d but i’m not sure. very sorry if i’m wrong
Step-by-step explanation:
