Question

The lenght of a rectangle is 4 meters more than twice the width. Find the greatest possible value for the width if the perimeter is at most 38 meters.

Answer 1

2(L + W) < = P
L = 2W + 4
P 38

2(2W+4 + W)  = 38
4W + 8 + 2W = 38
6W + 8 = 38
6W = 38 - 8
6W = 30
W = 30/6 = 5....the greatest possible value is 5