Answer:
hope it helps.
stay safe healthy and happy.
Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
G=m/x
G-gallons
m-miles
x-miles per gallon
19.2= 1293.6/x
x=1293.6/19.2
x= 67.375mpg
Therefore, the vehicle traveled 67.375 miles to 1 gallon
X= -1 beacuse negative one plus one is 0 and that will equal zero for both sides
To estimate 2641 x 9 is that you round each number. so it would be 2641 to 2640 and the 9 would round to 10. 2640 x 10