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r-ruslan [8.4K]
3 years ago
9

Justin is 3 years older then sam, and justin's age in 2 years will be twice what sam's age was 3 years ago. find their present a

ges.
Mathematics
1 answer:
sineoko [7]3 years ago
8 0
Justin 11 and sam 5.5
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aleksklad [387]
120 x (1/6) = 20 times
7 0
3 years ago
Which two numbers multiply to -52 and add to 24?
Shtirlitz [24]

Answer: -2 and 26

Step-by-step explanation:

-2 * 26 = -52

-2 + 26 = 24

5 0
3 years ago
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Six times a number a number increased by three is negative twenty-one. Find the number and write the equation
salantis [7]

let number be x

6x+3= -21

6x=-24

x=-4

3 0
2 years ago
In a batch of 100 parts, 40 are red, 50 are L-shaped and 22 are both red and L-shaped. What is probability that a part picked fr
Bogdan [553]

The probability that a part picked from this batch at random is either red or L-shaped is 0.68

Step-by-step explanation:

Let us revise some rules of probability

The addition rules are:

  • P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen  at the same time)
  • P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they  have at least one outcome in common)

∵ A batch has 100 parts

∵ 40 are red

- Probability of an event is the [even occurs/total outcomes]

∴ P(red) = \frac{40}{100}=0.4

∵ 50 are L-shaped

∴ P(L-shaped) = \frac{50}{100}=0.5

∵ 22 are both red and L-shaped

∴ P(red and L-shaped) = \frac{22}{100}=0.22

This is non-mutually exclusive because there is a common between them, so we will use the 2nd rule

∵ P(red or L-shaped) = P(red) + P(L-shaped) - P(red and L-shaped)

∴ P(red or L-shaped) = 0.4 + 0.5 - 0.22

∴ P(red or L-shaped) = 0.68

The probability that a part picked from this batch at random is either red or L-shaped is 0.68

Learn more:

You can learn more about the probability in brainly.com/question/2254182

#LearnwithBrainly

3 0
2 years ago
62.8 in scientific notation
bearhunter [10]

Answer:

6.28 x 10²

Step-by-step explanation:

first number must be greater than or equal to 1 and less than 10

if you move the decimal to the left you need to increase the power of ten by one for each move

if you move the decimal to the rightt you need to decrease the power of ten by one for each move

8 0
2 years ago
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