What is the slope of line that passes through the pair of points (4,7),(7,-2)

Marina CMI [18]

Answer:

Step-by-step explanation:

When we collect a large data we may find a single entry repeated. In these cases we prepare frequency distribution with x = the item in one column and f = the no of times it repeats i.e. frequency in other column.

Similarly for class intervals also, we write as frequency to the right side of interval column which gives no of items which fall within the class.

This process ensures compact presenting of data.

Hence we have

a)The number of observations that fall in a class

answer: Frequency

b) The relative frequency of a class multiplied by 100

answer: Percentage. Because when we express probability as a percentage we get total 100

c) The ratio of the frequency of a class to the total number of observations

answer: Relative frequency

(Relative frequency also known as probability is frequency/total entries)

8 0

2 years ago

Read 2 more answers

A school wants to attract more students to its media center. The media specialist has been asked to conduct a survey to determin

aliina [53]

I would say C or B but I may be wrong

6 0

3 years ago

Write the five term sequence that would represent each recursive rule f(x) = f(x-1) -7; f(2) = 12

barxatty [35]

<u>Answer: </u>

Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .

<u> Solution: </u>

Need to find the five terms of the sequence.

Given recursive rule is f(x) = f(x-1) -7

Substituting x = 2 , f(2) = f(2-1)-7

= f(2) = f(1) – 7 ------(1)

Also given that f(2) = 12.

On substituting the given value of f(2) in eq (1) we get

12 = f(1) – 7

f(1) = 12 + 7 = 19

Using given recursive rule and given value of f(2) calculating f(3)

Substituting x = 3 ,

f(3) = f(3-1) – 7

= f(2) – 7

= 12 – 7

= 5

Using given recursive rule and calculated value of f(3) calculating f(4)

Substituting x = 4,

f(4) = f(4-1) – 7

= f(3) – 7

= 5– 7

= -2

Using given recursive rule and calculated value of f(4) calculating f(5)

Substituting x = 5,

f(5) = f(5-1) – 7

= f(4) – 7

= -2– 7

= -9

Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .

8 0

2 years ago

Tina ate 21 starbursts. If she ate 35% of the package of Starbursts, how many Starbursts are in the package?

mojhsa [17]

Answer:

60 starbursts

Step-by-step explanation:

We can set up an equation to find the answer. 21/x=0.35/1 because we're trying to find how many starbursts make up 100% of the package. So then to solve, we take 21x1 and then divide that by 0.35. From this we find that x=60.

5 0

2 years ago

Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t

MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6. $\overline 6$

Given that 6. $\overline 6$ > 0, we have;

At the maximum volume, the width of the block, w = 6. $\overline 6$ cm ≈ 6.7 cm

The maximum volume, $V_{max}$ , is therefore given when w = 6. $\overline 6$ cm = 20/3 cm as follows;

V = 10·w² - w³

$V_{max}$ = 10·(20/3)² - (20/3)³ = 4000/27 = 148. $\overline {148}$

The maximum volume, $V_{max}$ = 148. $\overline {148}$ cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0

2 years ago