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dusya [7]
3 years ago
8

The number of problems assigned as homework by a savvy math professor is a function of the length of the class on a particular d

ay, which is either 45 minutes, 90 minutes, or 135 minutes. He first multiplies the number of minutes by 4 and then divides that number by 9. Finally, he subtracts 12 from that amount. Which of the following functions best represents the number of math problems the professor assigns depending on the length of the class, t, in minutes?
Mathematics
1 answer:
uysha [10]3 years ago
5 0

Answer:f(t)=4/9t — 12

Step-by-step explanation:

1. 4 is being multiplied by t first then divided by 9 not by 4/9 so there shouldn’t be any parentheses.

2. 12 is being subtracted from this so it should be 4/9t—12.

3. Final answer: f(t)= 4/9t — 12

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vekshin1

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Hope this helped!

5 0
3 years ago
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What is the area of a sector that has a radius of 25 mm and has an angle measure of 50°?
Nimfa-mama [501]

The area of the sector is 86.81π mm²

<u>Explanation:</u>

Given:

Radius of the sector, 25mm

Angle, α = 50°

Area of the sector, A = ?

We know:

Area of the sector = \frac{\alpha }{360} X \pi r^2

On substituting the value, we get:

A = \frac{50}{360} X \pi X (25)^2\\\\A = 86.81 \pi mm^2

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4 years ago
Please help me solving this problem.
Illusion [34]

(a) The radius of the circle is the distance the wave travels since it first formed, so if <em>g(t)</em> is the radius of the circle at time <em>t</em>, then it changes at a rate according to

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Integrate both sides with respect to <em>t</em> to solve for <em>g</em> :

∫ d<em>g</em>/d<em>t</em> d<em>t</em> = ∫ (60 cm/s) d<em>t</em>

<em>g(t)</em> = (60 cm/s) <em>t</em> + <em>C</em>

but <em>C</em> = 0 since the radius at <em>t</em> = 0 must be 0.

<em>g(t)</em> = (60 cm/s) <em>t</em>

<em />

(b) The area of any circle with radius <em>r</em> is <em>πr</em> ². So

<em>f(r)</em> = <em>πr</em> ²

(c) The composition of <em>f</em> with <em>g</em> represents the area of water encircled by the wave at time <em>t</em> :

<em>(f</em> o <em>g)(t)</em> = <em>f(g(t))</em> = <em>π</em> <em>g(t) </em>²

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marshall27 [118]

Answer:

1. B

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3. I

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