The slope is 3 or 3/1 and the Y intercept is 0 or (0,0) because in y=mx+b, is it the slope (3) and b is the y intercept (0)
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Answer:
Don't know the exact equation but trying to explain
X is what the stuff that problem saying. Let's say you have books from library and you're returning them late you will pay $30 dollars for each of them
Algebra is a very important branch of math.
Algebra is a lot like arithmetic which means it follows all the rules of arithmetic, and it still uses the four main operations that arithmetic is built on.
In arithmetic, the only thing that was unknown was the answer to the problem. For example, 39 + 2 = 41. In algebra, we use a variable to represent the number. A variable is a letter that represents any number. The most common variable is "x".
