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wlad13 [49]
3 years ago
8

All paper money in the united states is the same size no matter what the value is paper money has an area of about 16.86 square

inches and a length of about 6.1 inches what is the width of paper money
Mathematics
1 answer:
Mandarinka [93]3 years ago
5 0
Area is width times height.

16.86 = 6.1 w 

w = 16.86 / 6.1 = 2.76 inches approximately


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Myron got his paycheck of $40 this weck. He had $11 left after he spent m dollars on new video
solniwko [45]

Answer:

I dont know the answer but all I know is that dude broke as heck

6 0
3 years ago
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4. Solve. x² – 81 = 0 (1 point) 0 –9 –9, 9 9
Rudik [331]

x^2 - 81 = 0. Add 81 to each side.

x^2 = 81. Take the square root of each side.

x = 9, -9

5 0
3 years ago
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Aya = a1 + (n - 1)d
Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

Step-by-step explanation:

Given

  • a₁ = -33
  • d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

substituting a₁ = -33 and d = 4 in the nth term of the sequence

a_n=-33+\left(n-1\right)4

\:a_n=-33+4n-4

a_n=4n-37

Thus, the nth term of the sequence is:

a_n=4n-37

now substituting n = 26 in the nth term to determine the 26th term of the sequence

a_n=4n-37

a_{26}=4\left(26\right)-37

a_{26}=104-37

a_{26}=67

Therefore, the 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

7 0
2 years ago
9+10 please tell me.
Dima020 [189]
The answer would be 19.
8 0
3 years ago
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A.)List the 4 steps outlined in the lesson on solving equations.
aleksley [76]
1.) Solve for x:
5 x + 7 = 3 x + 21

Subtract 3 x from both sides:
(5 x - 3 x) + 7 = (3 x - 3 x) + 21

5 x - 3 x = 2 x:
2 x + 7 = (3 x - 3 x) + 21

3 x - 3 x = 0:
2 x + 7 = 21

Subtract 7 from both sides:
2 x + (7 - 7) = 21 - 7

7 - 7 = 0:
2 x = 21 - 7

21 - 7 = 14:
2 x = 14

Divide both sides of 2 x = 14 by 2:
(2 x)/2 = 14/2

2/2 = 1:
x = 14/2

The gcd of 14 and 2 is 2, so 14/2 = (2×7)/(2×1) = 2/2×7 = 7:
Answer:  x = 7

____________________________________________________________

2.)  Solve for x:
3 x - 2 (5 - x) = 3 x - 3 (x - 10)

-2 (5 - x) = 2 x - 10:
2 x - 10 + 3 x = 3 x - 3 (x - 10)

Grouping like terms, 3 x + 2 x - 10 = (3 x + 2 x) - 10:
(3 x + 2 x) - 10 = 3 x - 3 (x - 10)

3 x + 2 x = 5 x:
5 x - 10 = 3 x - 3 (x - 10)

-3 (x - 10) = 30 - 3 x:
5 x - 10 = 30 - 3 x + 3 x

3 x - 3 x = 0:
5 x - 10 = 30

Add 10 to both sides:
5 x + (10 - 10) = 10 + 30

10 - 10 = 0:
5 x = 30 + 10

30 + 10 = 40:
5 x = 40

Divide both sides of 5 x = 40 by 5:
(5 x)/5 = 40/5

5/5 = 1:
x = 40/5

The gcd of 40 and 5 is 5, so 40/5 = (5×8)/(5×1) = 5/5×8 = 8:

<span>Answer: x = 8

_________________________________________________________

3.) Solve for x:</span>
5 (x + 1) = 3 (2 x + 3) + 5

3 (2 x + 3) = 6 x + 9:
5 (x + 1) = 6 x + 9 + 5

Grouping like terms, 6 x + 5 + 9 = 6 x + (9 + 5):
5 (x + 1) = 6 x + (9 + 5)

9 + 5 = 14:
5 (x + 1) = 6 x + 14

Expand out terms of the left hand side:
5 x + 5 = 6 x + 14

Subtract 6 x from both sides:
(5 x - 6 x) + 5 = (6 x - 6 x) + 14

5 x - 6 x = -x:
-x + 5 = (6 x - 6 x) + 14

6 x - 6 x = 0:
5 - x = 14

Subtract 5 from both sides:
(5 - 5) - x = 14 - 5

5 - 5 = 0:
-x = 14 - 5

14 - 5 = 9:
-x = 9

Multiply both sides of -x = 9 by -1:
(-x)/(-1) = -9
(-1)/(-1) = 1:

<span>Answer: x = -9</span>
7 0
3 years ago
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