Equation in vertex form, y= (-1/4) x² + 4
<u>Step-by-step explanation:</u>
we have the equation,
y = ax² + 4 ( we need to find "a")
Now we have,
2 = a(4)2 + 4
2 = a (8)+ 4
2-4 = 8a
-2= 8a
a= -1/4
Substituting the value of "a" in the equation, we have
y = (-1/4)(x- 0)² + 4 (or) y= (-1/4) x² + 4
The parabola is opens downward. Therefore the vertex is above the x-axis and then the parabola passes through a point below the x-axis.
Equation in vertex form= y= (-1/4) x² + 4
3,062.85 is de answer having on two decimals
Answer:
7.5
Step-by-step explanation:
2x+12=6x-18
2x=6x-30
-4x=-30
x=7.5
Answer:
The angle between the given vectors u and v is ![\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B3%7D%7B%5Csqrt%7B10%7D%7D%5Cright%5D)
Step-by-step explanation:
Given vectors are 
and 
Now compute the dot product of u and v:
Now find the magnitude of u and v:
To find the angle between the given vectors
![\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%5Coverrightarrow%7Bu%7D.%5Coverrightarrow%7Bv%7D%7D%7B%7C%5Coverrightarrow%7Bu%7D%7C%5Coverrightarrow%7Bv%7D%7C%7D%5Cright%5D)
![=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]](https://tex.z-dn.net/?f=%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B15%7D%7B5%5Ctimes%20%5Csqrt%7B10%7D%7D%5Cright%5D)
Therefore the angle between the vectors u and v is
Answer:
yes
Step-by-step explanation:
every value of the domain only has one corresponding value
