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Liono4ka [1.6K]
2 years ago
6

Mr. Walker is looking at the fundraiser totals for the last five years.

Mathematics
1 answer:
klemol [59]2 years ago
7 0

Answer:

the median is $1.60 greater than the mean

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Simplify the equation.
maks197457 [2]

Answer:

Step-by-step explanation:

5(x-3y)+2(4x+y)-(x+y)

5x-15y+8x+2y-x-y

5x+8x-x-15y+2y-y

13x-x-13y-y

12x-12y

8 0
3 years ago
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What are the linear factors of 3x-13x+14
kow [346]

Answer:

-2(5x-7)

Step-by-step explanation:

Factor until each factor is linear

6 0
3 years ago
If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?
Alisiya [41]
If k is odd, then

\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor

while if k is even, then the sum would be

\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4

The latter case is easier to solve:

\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0

which means k=6.

In the odd case, instead of considering the above equation we can consider the partial sums. If k is odd, then the sum of the even integers between 1 and k would be

S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)

Now consider the partial sum up to the second-to-last term,

S^*=2+4+6+\cdots+(k-5)+(k-3)

Subtracting this from the previous partial sum, we have

S-S^*=k-1

We're given that the sums must add to 2k, which means

S=2k
S^*=2(k-2)

But taking the differences now yields

S-S^*=2k-2(k-2)=4

and there is only one k for which k-1=4; namely, k=5. However, the sum of the even integers between 1 and 5 is 2+4=6, whereas 2k=10\neq6. So there are no solutions to this over the odd integers.
5 0
3 years ago
Mrs.Douglas wanted to give each of her students 3 fancy pencils. She has 20 students. If fancy pencils come in packs of 12, how
Colt1911 [192]
1 pack of 12 will give 4 students their pencils. 20/4 = 5
3 0
2 years ago
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TIMED HELP! Pilar wanted to use estimation to solve a decimal addition problem. She correctly used estimation to rewrite the pro
Neko [114]

D. 11.75 + 3.299 + 5.31 + 6.27

Step-by-step explanation:

11.75 would round up to 12, 3.299 would round down to 3, 5.31 would round down to 5 and 6.27 would round down to 6

4 0
3 years ago
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