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S_A_V [24]
3 years ago
14

Which unit of measurement would be the most appropriate to measure the capacity of a large vase?

Mathematics
2 answers:
Ber [7]3 years ago
4 0
Liter

Explanation

The liter is most appropriate for an average volume like that of a big vase
artcher [175]3 years ago
3 0

Answer:

liter

Step-by-step explanation:

the liter is the most likely unit of measurement for this case

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Mila [183]

Answer:

Multiply liters by 10.

1 liters= 10 deciliters

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3 years ago
The bucket containing orange tennis balls and yellow tennis balls from which 5 balls are selected at random, but assume that the
NeX [460]

(1)  

Probability that all are yellow = \frac{7\times6\times5\times4\times3}{16\times15\times14\times13\times12}=0.0048

Probability that all are orange = \frac{9\times8\times7\times6\times5}{16\times15\times14\times13\times12}=0.0288

Sum of the two probabilities = 0048+ 0.0288=0.0336

Thus, the probability that at least one is orange and at least one is yellow = 1-0.0336= 0.9664= 96.64 %


(2) In addition to the above, we eliminate the "1 and 4" cases.  

In these cases, any of the 5 can be taken out, so we multiply by 5.  


1 yellow + 4 orange = 5\times \frac{(7 \times 9 \times 8 \times 7 \times 6)}{(16 \times 15 \times 14 \times 13 \times12)}  = 0.2019

1 orange + 4 yellow = 5 \times \frac{(9 \times 7\times 6 \times 5 \times 4)}{(16 \times 15\times 14 \times 13 \times 12)} = 0.0721


Sum of two probabilities = 0.2019+0.0721=0.2740  

Now adding 0.0336 to this probability =0.0336+0.2740= 0.3076  


Subtracting that from 1.0000 = 1-0.3076=0.6924= 69.24 %

Thus, the probability that, of the 5 balls selected at random, at least two are orange and at least two are yellow= 69.24%


4 0
3 years ago
-2/3,0.6,3/4,-7/4,0,3 from least to greatest
Alja [10]

Answer:

-7/4 < -2/3 < 0 < 0.6 < 3/4 < 3

Step-by-step explanation:

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How many 2/3 foot pieces can Wendy cut from the 51/3 feet of ribbon
Katen [24]

You would divide 51 by 2 to get the answer, as the units are the same, for an answer of 25 two-thirds foot sized pieces, with 1 as a remainder.

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3 years ago
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