Question

If p(x) = (x - 1) (x + 1), then find the value of p(2) + p(1) - p(0)

Answer 1

Answer:

4

Step-by-step explanation:

$p(x) = (x - 1) (x + 1) \\ plug \: x = 2 \: 1 \: 0 \: we \: find: \\ \\ p(2) = (2 - 1) (2 + 1) = (1)(3) = 3 \\ p(1) = (1 - 1) (1 + 1) = (0)(2) = 0 \\ p(0) = (0 - 1) (0 + 1) = ( - 1)(1) = - 1 \\ \\ p(2) + p(1) - p(0) \\ = 3 + 0 - ( - 1) \\ = 3 + 1 \\ = 4$