Please helP!! I don't know how to do this!!
1 answer:
2.25:1
Substitute the "new" velocity (I.e. "1.5v") into the dynamic pressure equation:
q = (1/2)*n*[(1.5v)^(2)]
=> q= (1/2)*n*[2.25v^(2)]
Compare this result to dynamic pressure with a velocity of "v":
q = (1/2)*n*[v^2]
As you will see, the faster fluid has a dynamic pressure, q, value that is 2.25x greater than that of the slower fluid.
Therefore, the ratio of the faster fluid to the slower fluid is 2.25 to 1.
You might be interested in
Explanation:
hope it helps you and give me a brainliest
5.2 gallons you multiply 20*.26
The answer is William Parker.
Answer:
found in a limited time span
They can’t cancel each other and if you were to keep going it would give an incorrect fraction for solution :)
