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KATRIN_1 [288]
3 years ago
5

Please helP!! I don't know how to do this!!

SAT
1 answer:
zalisa [80]3 years ago
3 0
2.25:1

Substitute the "new" velocity (I.e. "1.5v") into the dynamic pressure equation:

q = (1/2)*n*[(1.5v)^(2)]
=> q= (1/2)*n*[2.25v^(2)]

Compare this result to dynamic pressure with a velocity of "v":

q = (1/2)*n*[v^2]



As you will see, the faster fluid has a dynamic pressure, q, value that is 2.25x greater than that of the slower fluid.

Therefore, the ratio of the faster fluid to the slower fluid is 2.25 to 1.
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