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3 years ago

Find the surface area of this rectangular prism. Be sure to include the correct unit in your answer.

Mathematics

1 answer:

OLEGan [10]3 years ago

5 0

Answer:

136

Step-by-step explanation:

Area of top and bottom added together:

(6) (7) + (6) (7)

42 + 42

Area of front and back added together:

(7) (2) + (7) (2)

14 + 14

Area of left and right added together:

(2) (6) + (2) (6)

12 + 12

Add all underlined numbers:

Area of top and bottom + Area of front and back + Area of left and right

84 + 28 + 24

136

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1. Simplifying ∛54 gives 3∛2

2. 27^1/3 * (27)^3 is equal to 27

3. The expression (2j4k)^4/5 can be written as $\sqrt[4]{32j^{20}k^{5} }^{5}$ making the first option the correct option

4. simplifying $\sqrt[4]{16x^{4} y^{12} }$ will result to 2x∛y

5. simplifying $\sqrt[5]{2940x^{13} y^{7} }$ will result to $14x^{6} y^{3} \sqrt{15xy}$ making the last option the correct option

<h3>How to simplify $\sqrt[5]{2940x^{13} y^{7} }$ </h3>

<u>given data</u>

$\sqrt[5]{2940x^{13} y^{7} }$

= ( 2940 * x^13 * y^7 )^1/5

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5}$

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5*5/2}$

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{5/5*1/2}$

multiplying the values inside the parenthesis by ^1/2

$= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )$

$= ( 14* 5^{1/2} * 3^{1/2} * x^{6} * x^{1/2} * y^3 * y^{1/2} )$

$= ( 14 * x^6 * y^3 ) ( 5^{1/2} * 3^{1/2} * x^{1/2} * y^{1/2} )$

$= ( 14x^6y^3 ) ( 15^{1/2} * x^{1/2} * y^{1/2} )$

$= ( 14x^6y^3 ) ( 15xy)^{1/2}$

$= ( 14x^6y^3 ) \sqrt{( 15xy)}$

we can therefore say that the last option is the answer

Read more on equations here: brainly.com/question/22688504

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