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zheka24 [161]
3 years ago
14

What set of reflections would carry rectangle ABCD onto itself?

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

  y=x, x-axis, y=x, y-axis

Explanation:

Reflecting the figure across three axes just moves it from one quadrant to another. It does not map the figure to itself.

Reflecting across the line y=x moves it from quadrant II to IV or vice-versa. If it is in quadrant I or III, it stays there. So the sequence of reflections x-axis (moves from I to IV), y=x (moves from IV to II), x-axis (moves from II to III), y=x (stays in III) will not map the figure to itself.

However, the last selection will map the figure to itself. The initial (and final) figure location, and the intermediate reflections are shown in the attached. The figure starts and ends as blue, is reflected across y=x to green, across x-axis to orange, across y=x to red, and finally across y-axis to blue again.

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The function f(x) = 3x² + 12x +11 can be written in
Viktor [21]

Answer:

3)  f(x) = 3(x + 2)^2 - 1.

Step-by-step explanation:

f(x) = 3x² + 12x +11

f(x) = 3(x^2 + 4x) + 11        Completing the square:

f(x) =  3[(x + 2)^2 - 4] + 11

f(x) = 3(x + 2)^2 -+3*-4 + 11

f(x) = 3(x + 2)^2  - 12 + 11

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6 0
3 years ago
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8 0
3 years ago
What is the area of a tringe with a base of 16cm and a height of 5ft plus the area of a rectangle with the height of 19cm and wi
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6 0
1 year ago
The top of the desk is shaped like a trapezoid the bases of the trapezoid are 26.5 and 30 cm long the area of the desk is 791 CM
kotegsom [21]

Answer:

28 cm

Step-by-step explanation:

Given that :

Area = 791 cm

Base, b1 = 26.5 cm

Base, b2 = 30 cm

Area, A of trapezoid :

A = 1/2 (a + b) h

Where a and b are the bases ;

791 = 1/2(26.5 + 30)h

791 = 0.5(56.5)h

791 = 28.25h

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5 0
3 years ago
Find the value of the variable and GH if H is between G and I. GI=5b+1, HI=4b-5, HI=7
fgiga [73]

Answer:

The value of the variable 'b' is 3 and GH is 9

Step-by-step explanation:

Given:

GI = 5b+1\\\\HI=4b-5\\ \\HI=7

H is between G and I

Such that G - H - I

To Find:

GH = ?

Solution:

On Substituting HI we get

4b-5=7\\\\\therefore 4b=7+5=12\\\\b=\dfrac{12}{4}=3

Substituting 'b' in HI and GI we get

HI=4\times 3 -5=12-5=7\\\\\therefore HI = 7

GI=5\times 3 +1=15+1=16\\\\\therefore GI = 16

Now, by Line Addition Property we get

GI=GH+HI

Substituting 'HI' and 'GI' we get

16=GH+7\\\\\therefore GH=16-7=9

The value of the variable 'b' is 3 and GH is 9

4 0
3 years ago
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