Answer:
the correct answer is $150
Explanation:
TC=500 + 150q - 20q^2 + q^3
AVC=(150Q-20Q^2+Q^3)/Q
=150-20Q+Q^2
When AVC is at its minimum means that the marginal cost( CM) is igual to AVC, so we could consider this analysis:
CM= d(TC)/dq =150-40Q+3Q^2
CM=AVC
150-40Q+3Q^2=150-20Q+Q^2
Join similar terms:
150-150-40Q+20Q+3Q^2-Q^2=0
0-20Q+2Q^2=0
Q(-20+2Q)=0
Q_1=0 y Q_2=20/2=10
with q_1 with q_2
150-40*0+3*0=150-20*0+0 150-40*10+3*10^2=150-20*10+10^2
$150=$150 150-400+300 =150-200+100
$50= $ 50
We have two solution if we assume that q=0 like the minimum then the results is $150.
f we assume that q=10 like the minimum then the results is $50.
Answer:
Explanation:
Cash Payment to customers: $450,000 x contract rate of 9% x 1/2 = $20,250
Amortization of the premium: $11,795/6 periods = $1,966
Bond interest Expense: $20,250 - $1966 = $18,284
Answer:$119,735.6
Explanation:
To calculate the total in the account,we use the compound interest formula
A= P ( 1+ ( R/2)/100)∧2n
P = $ 12,000 n = 4 R = 12%
A = 12,000 (1+(12/2/100)∧2*4
A = 12,000 ( 1+ ( 6)/100)∧2*4
A = 12,000 ( 1+0.06)∧8
A= 12,000 ( 1.06)∧8
A = 12,000 ( 1.5938)
A= 12,000* 1.5938
A= $ 19,125.6
Another deposit into the account
A = P ( 1+(R/2)/100)∧2n
A= 50,000 (1+12/2/100)∧2*6
A= 50,000 (1+6/100∧12
A = 50,000 ( 1+0.06)∧12
A = 50,000 (1.06)∧12
A= 50,000 ( 2.0122)
A = 50,000* 2.0122
A = 100,610
Therefore, the total in the account
$19,125.6 + $100,610
= $119,735.6
