All categories

4 years ago

HELPPPPPPPPPPPPPPPPPPP and explain

Mathematics

1 answer:

ohaa [14]4 years ago

3 0

1000÷2=500
1000÷5=200
1000÷10=100
of the integers between 0 and 1000, when 1000 in not included, (it says less than 1000, so I believe 1000 in not included), there are 499 numbers divisible by 2, 199 numbers divisible by 5, and 99 numbers divisible by both 2 and 5
so 499+199-99=599
the answer is d.

You might be interested in

Can someone help me find the answers!

PIT_PIT [208]

First answer: 9.342

Second answer: 416.66

3 0

3 years ago

How many 0.4-liter glasses of water does it take to fill up a 3.4 -liter pitcher? Please help

Hatshy [7]

Let n = number of glasses needed
1 glass gives us 1*0.4 = 0.4 liters of water
2 glasses give us 2*0.4 = 0.8 liters
3 glasses give us 3*0.4 = 1.2 liters
4 glasses give us 4*0.4 = 1.6 liters
and so on...
In general,
n glasses give us n*0.4 = 0.4*n liters of water

So 0.4*n is going to be the same as 3.4 as we want to fill the 3.4 liter pitcher.
Set 0.4*n equal to 3.4 and solve for n

0.4*n = 3.4
0.4*n/0.4 = 3.4/0.4 <<--- divide both sides by 0.4
n = 8.5

If we want n to be a whole number, then round up to the nearest whole number. So we'll need 9 full glasses of water to fill the 3.4 liter pitcher. There is extra water in this case which isn't used.

So the answer is either 8.5 or 9 depending on if your teacher wants you to round to the nearest whole number.

7 0

3 years ago

Read 2 more answers

What is the rate of decay in the following function?<br><br> f(x)=3(67)^x

tigry1 [53]

Answer:

Suppose N is the size of a population of radioactive atoms at a given time t, and dN is the amount by which the population decreases in time dt; then the rate of change is given by the equation dN/dt = −λN, where λ is the decay constant.

5 0

2 years ago

the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region

m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

$\frac{x}{360} \pi {r}^{2}$

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

$16 = \sqrt{10 {}^{2} + 10 {}^{2} - 2(100) \times \cos(o) }$

This isn't the standard formula, it's for this problem

$16 = \sqrt{200 - 200 \times \cos(o) }$

$16 = \sqrt{200 - 200 \cos(o) }$

$256 = 200 - 200 \cos(o)$

$56 = - 200 \cos(o)$

$- \frac{7}{25} = \cos(o)$

$\cos {}^{ - 1} ( - \frac{7}{25} ) = \cos {}^{ - 1} ( \cos(o) )$

$106.26 = o$

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

$\frac{106.26}{360} (100)\pi$

$\frac{10626}{360} \pi$

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

$\sqrt{s(s - a)(s - b)(s - c)}$

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

$\frac{36}{2} = 18$

$\sqrt{18(18 - 10)(18 - 10)(18 - 16)}$

$\sqrt{18(8)(8)(2)}$

$\sqrt{(36)(64)}$

$6 \times 8 = 48$

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

$\frac{10626}{360} - 48$

Which is an approximate or

44.73

6 0

2 years ago

Given a polynomial f(x), if (x − 6) is a factor, what else must be true?

puteri [66]

Answer:

below.

Step-by-step explanation:

f(6) = 0 because (x - 6) ---> (6 - 6) = 0

7 0

3 years ago