<u>The interpreter attended </u><u>22 parent-teacher conference</u><u> and </u><u>5 school related assembly</u>
To solve this problem, we would write out two set of linear equations.
The data given on this problem are
- parent-teacher conference = $35.50
- school related assembly = $42
- The total number of engagements = 27
Let x represent the number of parent-teacher conference
let y represent the number of school related conference
<h3>Equations</h3><h3>

</h3>
From equation (i)

Put equation(iii) into equation (ii)

Put y = 5 into equation 1

From the above calculations, he attended 22 parent-teacher conference and 5 school related assembly.
Learn more on linear equations here;
brainly.com/question/4074386
The range of the top plot, hours spent by 13-15 year olds, is found by subtracting the highest value, 34, and the lowest value, 21. 34-21=13.
The mean of the top plot is found by adding together all of the data points and dividing by 10 (the number of data points):

The range of the bottom plot, minutes spent online by 16-18 year olds, is found by subtracting the highest value, 36, and the lowest value, 12. 36-12=24.
The mean of the bottom plot is found by adding together all of the data points and dividing by 11 (the number of data points):
13.60 !
because i calculated
<h3>
Answer:</h3>
- sticker: $12,620
- dealer's cost: $10,712
<h3>
Step-by-step explanation:</h3>
The total cost of options is the sum of their individual costs.
total options = $542 +140 +318 +580 = 1580
The sticker price is ...
sticker price = base price + total options + destination charge
= $10600 +1580 +440
sticker price = $12,620
The dealer cost is ...
dealer cost = 82% × base price + 100% × total options + destination charge
= 0.82·$10600 +1580 +440
dealer cost = $10,712