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4 years ago

What is 5/6 as a percent rounded to the nearest hundredth

1 answer:

6 0

To find the percent, we first find the decimal.

To do that we divide 5 / 6, which gives us approximately 0.83333, now we multiply it by 100 since percentages are parts of 100.

0.83333 * 100 = 83.33%

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The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the

ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/ $\sqrt{n}$ )

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/ $\sqrt{n}$

The upper limit => C.I_u = μ + Z*σ/ $\sqrt{n}$

The lower limit => C.I_l = μ - Z*σ/ $\sqrt{n}$

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/ $\sqrt{n}$ )

= 200 + (1.96*30)/ $\sqrt{n}$

= 200 + 58.8/ $\sqrt{n}$

5 0

3 years ago

Can you help me with this question

love history [14]

Answer:

x=−7/2,−1+i√2−1−i√2

Step-by-step explanation:

5 0

3 years ago

A) What is the value of 6^2 b) What is the value of square root of 81

Sholpan [36]

Answer:

6²= 6×6= 36

√81= 9

hope it helps! please mark me brainliest

thank you!! have a good day ahead!

3 0

3 years ago

Read 2 more answers

8) through: (-3, -2), perp. to y = x – 1 A) y=-5x – 1 B) y=-4x – 5 C) y=-x – 5 D) y=-5x – 4

nexus9112 [7]

Answer:

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

Solution:

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1$

We know that, product of slopes of perpendicular lines is -1.

So, 1 $\times$ slope of perpendicular line = -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

$\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)$

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0

4 years ago

Why are all the questons just for 5 points no one choses higher

ValentinkaMS [17]

Answer:

I don't know I want even let me choose 5

3 0

3 years ago