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3 years ago

Select all the correct locations on the map.

Mathematics

2 answers:

Bingel [31]3 years ago

4 0

India and africa (i think the third one is arabia but i'm not sure)

SVEN [57.7K]3 years ago

3 0

Answer:

The Correct answers are, the top two (a and d), and the very bottom one (c).

Step-by-step explanation:

I got the answers right in my test!

Have a great day!!

You might be interested in

A train leaves at 14:56 and arrives at 16:43. It travelled at an average speed of 135 km/h. How far did it travel? Give your ans

Firlakuza [10]

Answer:

240.8

Step-by-step explanation:

→ Calculate time taken

16:43 - 14:56 = 1 hour and 47 minutes

→ Write the speed formula and make distance the subject

Speed = Distance ÷ Time ⇔ Distance = Speed × Time

→ Convert 1 hour and 47 minutes into decimal format

1.78333333 or $1\frac{47}{60}$

→ Substitute values into formula

135 × $1\frac{47}{60}$ = 240.75

8 0

3 years ago

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: