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VikaD [51]
2 years ago
10

The sum of the digits of a 5-digit-priced car totals 15. You know that no digit repeats and that the fourth digit of the car is

a 7 (meaning the sum of the remaining four digits is 8). How many different sets of numbers can you pick for the other four digits? Assume each digit can be used only once with no repetitions and you only need to pick the digits--not the order in which they go.
Mathematics
1 answer:
bulgar [2K]2 years ago
6 0
You can pick as many numbers as you can as long as it adds up to a particular number trust me i took this.
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Answer:

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Step-by-step explanation:

37.75=b+s+p

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33.75=1/6(3/4p)+3/4p+p

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37.50=2p)/2

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3/4(18.75)

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7 0
2 years ago
Can anyone help me with this please!!
Levart [38]

Answer:

22.88 cm^3

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3 years ago
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