Question

Write an equation in slope-intercept form of the line that passes through (6,-2) and (12,1)

Answer 1

Equation in slope-intercept form of the line that passes through (6,-2) and (12,1) is:

$y =\frac{1}{2}x-5$

Step-by-step explanation:

Given points are:

(x1,y1) = (6,-2)

(x2,y2) = (12,1)

The slope intercept form is:

$y=mx+b$

We have to find the slope first

$m =\frac{y_2-y_1}{x_2-x_1}\\=\frac{1-(-2)}{12-6}\\= \frac{1+2}{6}\\=\frac{3}{6}\\=\frac{1}{2}$

Putting the value of slope

$y = \frac{1}{2}x+b$

To find the value of b, putting (12,1) in the equation

$1 = \frac{1}{2}(12)+b\\1 = 6+b\\b = 1-6\\b=-5$

Putting the values of m and b

$y =\frac{1}{2}x-5$

Hence,

Equation in slope-intercept form of the line that passes through (6,-2) and (12,1) is:

$y =\frac{1}{2}x-5$

Keywords: Equation of line, slope-intercept form

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