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Alex73 [517]
3 years ago
14

Write an equation in slope-intercept form of the line that passes through (6,-2) and (12,1)

Mathematics
1 answer:
yarga [219]3 years ago
8 0

Equation in slope-intercept form of the line that passes through (6,-2) and (12,1) is:

y =\frac{1}{2}x-5

Step-by-step explanation:

Given points are:

(x1,y1) = (6,-2)

(x2,y2) = (12,1)

The slope intercept form is:

y=mx+b

We have to find the slope first

m =\frac{y_2-y_1}{x_2-x_1}\\=\frac{1-(-2)}{12-6}\\= \frac{1+2}{6}\\=\frac{3}{6}\\=\frac{1}{2}

Putting the value of slope

y = \frac{1}{2}x+b

To find the value of b, putting (12,1) in the equation

1 = \frac{1}{2}(12)+b\\1 = 6+b\\b = 1-6\\b=-5

Putting the values of m and b

y =\frac{1}{2}x-5

Hence,

Equation in slope-intercept form of the line that passes through (6,-2) and (12,1) is:

y =\frac{1}{2}x-5

Keywords: Equation of line, slope-intercept form

Learn more about equation of line at:

  • brainly.com/question/4361464
  • brainly.com/question/4390083

#LearnwithBrainly

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