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Rainbow [258]
4 years ago
15

The number of goals scored by a hockey team in each of its first 10 games is 2, 4, 0, 3,4, 1, 3, 1, 1, and 5. Find the mean numb

er of goals scored
Mathematics
1 answer:
Artemon [7]4 years ago
6 0
The mean is the average number from the group of numbers.
In this case, the average of the numbers 2, 4, 0, 3, 4, 1, 3, 1, 1, 5 is 2.4.
This is discovered by adding all the numbers together (which in this case is 24) and dividing that number by the amount of numbers in the group (in this case it's 10). 
24 ÷ 10 = 2.4
Therefore the mean is 2.4.
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Use the Distance Formula to find the distance between (-3, 7) and (8,- 6), rounded to the nearest hundredth.
faust18 [17]

Answer:

  17.03 units

Step-by-step explanation:

The distance formula for the distance between two points (x1, y1) and (x2, y2) is ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

For the given points, the distance is ...

  d = √((8-(-3))^2 +(-6-7)^2) = √(11^2 +(-13)^2)

  d = √(121 +169) = √290

  d ≈ 17.03

The distance between the points is about 17.03 units.

8 0
4 years ago
Can someone please answer the last one
rewona [7]
He cannot run 5km in 15.25 minutes
8 0
3 years ago
Identify the segment bisector of AB¯¯¯¯¯¯¯¯. Then find AB.
tia_tia [17]

Answer:

is there more to the question? this does not make seince  

Step-by-step explanation:

5 0
3 years ago
Which graph represents the solution set of the system of inequalities?<br> y&lt;−3x−2<br> y≤x−2
kotegsom [21]

It would be the first graph

That is because the 2nd and 3rd graphs start at a point close to (0,-2) but it is not the correct point.

Now using (0,0) as a solution plug it in for the x and y values like so

0 <−3(0)−2 = 0 < -2

0 ≤ 0 −2 = 0 ≤ -2

This does not work so solutions from (0,0) up cannot be solutions, so the first graph must be the right answer.  

5 0
3 years ago
Each of a sample of four home mortgages is classified as fixed rate (F) or variable rate (V). (Enter your answers as a comma-sep
omeli [17]

Answer:

a)

{FVVV,FFVV,VFVV,VVVV,FVFV,FFFV,VFFV,VVFV,FVVF,FFVF,VFVF,VVVF,FVFF,FFFF,VFFF,VVFF}

b)

{FFFV,FFVF,FVFF,VFFF}

c)

{FFFF,VVVV}

d)

{FFFV,FFVF,FVFF,FFFF,VFFF}

e)

{FFFV,FFVF,FVFF,FFFF,VFFF,VVVV}

{FFFF}

f)

{FFFV,FFVF,FVFF,VFFF,FFFF,VVVV}

{ }

Step-by-step explanation:

a)

The 16 outcomes for a sample of four home mortgages classified as fixed and variable rate are

Sr.No Outcomes

1          FVVV

2         FFVV

3         VFVV

4         VVVV

5         FVFV

6         FFFV

7         VFFV

8         VVFV

9         FVVF

10        FFVF

11         VFVF

12        VVVF

13        FVFF

14        FFFF

15        VFFF

16        VVFF

b)

Let A be the event that exactly three are fixed rate. Thus, event A consists of following outcomes

A={FFFV,FFVF,FVFF,VFFF}

c)

Let B be the event that all four are of same type. The event B consists of either all fixed rate or all variable rate. Thus, event B consists of following outcomes

B={FFFF,VVVV}

d)

Let C be the event that at most one of four is variable rate. The event C consists of less than and equal to one variable rate. Thus, event C consists of following outcomes

C={FFFV,FFVF,FVFF,FFFF,VFFF}

e)

Let union of part(c) and part(d) can be represented as BUC. The union represents all the outcomes in event B and event C.

B∪C={FFFF,VVVV}∪{FFFV,FFVF,FVFF,FFFF,VFFF}

B∪C={FFFV,FFVF,FVFF,FFFF,VFFF,VVVV}

Let intersection of part(c) and part(d) can be represented as B∩C. The intersection represents the common outcomes in event B and event C.

B∩C={FFFF,VVVV}∩{FFFV,FFVF,FVFF,FFFF,VFFF}

B∩C={FFFF}

f)

Let union of part(b) and part(c) can be represented as AUB. The union represents all the outcomes in event A and event B.

A∪B={FFFV,FFVF,FVFF,VFFF}∪{FFFF,VVVV}

A∪B={FFFV,FFVF,FVFF,VFFF,FFFF,VVVV}

Let intersection of part(b) and part(c) can be represented as A∩B. The intersection represents the common outcomes in event A and event B.

A∩B={FFFV,FFVF,FVFF,VFFF}∩{FFFF,VVVV}

A∩B={ }

So intersection of part(b) and part(c) is an empty set as there is no common outcome in these two sets.

8 0
3 years ago
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