All categories

2 years ago

Somebody help I’m stuck :(

Mathematics

1 answer:

ANEK [815]2 years ago

3 0

Answer:

I got x1 =0 x2=220

Step-by-step explanation:

y=- 00.1x (x-220)

-0.01x (x-220)=0

- 1/100 x(x-220)=0

x (x-220)=0

x=0

x-220=0

Answer x=0 and x=220

You might be interested in

EMERGENCY!! PLEASE HELP ME IMMEDIATLEY PLEASE!!!PLEASE HELP MEEEE!!!!

denis23 [38]

Answer:

y=1/2-2

Step-by-step explanation:

3 0

2 years ago

Date

Ivahew [28]

Answer:

Boiling point of jet fuel = 165 degrees Celsius

Step-by-step explanation:

Given:

Boiling point of jet fuel = 329°F

Find:

Boiling point of jet fuel in degrees Celsius

Computation:

C = [5/9][F – 32]

C = [5/9][329 – 32]

C = 165

Boiling point of jet fuel = 165 degrees Celsius

6 0

3 years ago

Help please due today

Readme [11.4K]

I’m pretty sure Scale drawings is the correct answer!

6 0

3 years ago

Read 2 more answers

What is the answer to 3 and 5 7ths - 3 and 2 sevanths

Sergeeva-Olga [200]

Its 3/7
$\frac{3}{7}$

4 0

3 years ago

Read 2 more answers

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago