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2 years ago

11

Emily is saving up to buy a new phone. She already has $75 and can save an additional $7 per week using money from her after sch

ool job. How much total money would Emily have after 4 weeks of saving? *

2 answers:

Softa [21]2 years ago

4 0

Answer:$28

Step-by-step explanation: 7 x 4

<em><u>***INCORRECT***</u></em>

Yuki888 [10]2 years ago

3 0

Anwser - 103$$$$$$$$$$$$$$$$

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Find the domain of the graphed function. Help me please);

pogonyaev

The correct answer is B. -4<x<2.

This is because the domain is looking for the values of x that can be used in the function. In the picture below, you will notice that the leftmost point is at x = -4. This is as low as the x value goes. The rightmost point is at x = 2, which is as large as the x value gets. Therefore the domain is between those two numbers.

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Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of <em>t</em> for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

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2 years ago

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Mandarinka [93]

Answer:

based on yahoo, cause my iq is like 10...the answer is B

Step-by-step explanation:

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(10v^3 + 71v^2 + 11v+23) / (v+ 7)

vlabodo [156]

tell us the question so we can help.

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2 years ago

Which rational exponent represents a cube root? A. 3/2 B. 1/2 C. 1/4 D. 1/3

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