Answer:
3x+2y
Step-by-step explanation:
you would count 3 to the right on the flat line, and on the line that goes straight up and down, you would count 2 going up and you would plant a dot where they meet on the graph
True
The pythagorean theorem only needs two sides of a right triangle
Answer:
(a) P = 2x + 2r + 2πr
(b) x = ½(P - 2r - 2πr)
(c) x = 123 feet
Step-by-step explanation:
See Attachment for sketch of the track
Solving for (a): Perimeter of the track
This is calculated by adding the perimeter of the rectangle to the 2 semicircles as follows.
P = Perimeter of Rectangle + Perimeter of 2 Semicircles
P = 2(x + r) + 2 * πr
[Where r is the radius of both semicircles]
Open bracket
P = 2x + 2r + 2πr
Solving for (b): Formula for x
P = 2x + 2r + 2πr
Make x the subject of formula
2x = P - 2r - 2πr
Divide both sides by 2
x = ½(P - 2r - 2πr)
Solving for (c): the value of x when r = 50 and P = 660
Substitute the given values in the formula in (b) above
x = ½(P - 2r - 2πr)
x = ½(660 - 2 * 50 - 2π * 50)
x = ½(660 - 100 - 100π)
x = ½(560 - 100π)
Take π as 3.14
x = ½(560 - 100 * 3.14)
x = ½(560 - 314)
x = ½ * 246
x = 123 feet
Answer:
w = (p - 21)/2
Step-by-step explanation:
Rearrange the equation so that it is equal to w.
p = 21 + 2w
p - 21 = (21 + 2w) - 21
p - 21 = 2w
(p - 21)/2 = (2w)/2
(p - 21)/2 = w
w = (p - 21)/2
Answer:
The rule that represents the function is
therefore the function is 
Step-by-step explanation:
We have 5 ordered pairs in the plane xy. This means that <em>every pair has the form (x, y).</em>
Then, we have 5 values of x, which will give us 5 values of y, using the rule that represents the function.
<u>The easy evaluation is that when x=0, the value of y is y=1,</u> and then we can evaluate the rule for x=-1, and x=1, <em>the value of y is the same, y=2</em>. We can see here that we have a parabolic function, that is not centered in the origin of coordinates because when x=0, y=1.
So <u>we propose the rule </u>
<u> which is correct for the first 3 values of x.</u>
Now, <em>we evaluate the proposed rule when x=2, and when x=3</em>. This evaluations can be written as


Therefore, the rule is correct, and the function is
