Answer:
The solution is 0, 90 molal. See the explanation below, please
Explanation:
Molality is defined as moles of solute in 1 kg of solvent (1000 grams). The following three simple rule must be performed:
We calculate the weight of 1 mol of CaCl2
Weight Ca =40, 078 g
Weight Cl= 35, 453 g
Weight of 1 mol of CaCl2=40, 078g + 2x (35, 453g )= 110, 98g
110, 98 g ---1 mol
25 g---X= (25g x1 mol)/110, 98g= 0,23mol
250g solvent -----0,23 mol CaCl2 (the solute)
1000g solvent ----X = (1000g x0,23mol)/250g =0,90 mol solute
The solution is 0,90 molal
Lowercase b is the allele that goes in 3
V final = (Mass x V initial) + (Mass x V initial) /m + m
V = (0.04 x 300) + ( 0.5 x 0 ) / 0.04 + 0.5
V = 22.2 m/s
The blood has low oxygen content
