Calculus 1?
To find concavity you must take the second derivative.
As you would to find your local maximums and minimums (critical points) in the first derivative by setting y' = 0, to find points of inflection you set acceleration, y" = 0.
Now that you know where the point in which the function is neither concave up or concave down (at the points of inflection) plug x-values between them into the second derivative for x. If y" is positive between those particular points will be concave up and if y" is negative it will be concave down between that interval.
For a better understanding you might find a good video on Youtube explaining this if you search "Points of Inflections" or "Concavity of a function".
Cheers.
Answer: Determine whether each set equipped with the given operations is avector space. For those that are not vector spaces identify the vector space axioms that fail.a). The set of all pairs of real numbers of the form (x,y), where x ≥ 0, with the standard operations on R^2.b). The set of all triples of real numbers with the standard vectoraddition but with scalar multiplication defined by k(x,y,z) = (k^2x,k^2y,k^2z)c). The set of all 2 x 2 invertible matrices with the standard matrix addition and scalar multiplication
Step-by-step explanation:
Step-by-step explanation:
Given
The pair of lines are
For the first line, if y=0, x=2
if x=0, y=-4
Similarly, for second line , if y=0, x=-2
if x=0, y=2
Plot the given point and draw the line.
From the graph the two lines meet at (6,8)
Answer:
a × 2 means 'a' multiplied by 2
a(2) also means 'a' multiplied by 2
So both mean the same.
