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-Dominant- [34]
3 years ago
10

How do you verify this trig identity?

Mathematics
2 answers:
fiasKO [112]3 years ago
7 0

Answer:

Step-by-step explanation:

\frac{ \sin(x) \csc(x) }{ \cot(x) }

cot(x)

sin(x)csc(x)

Rewrite csc(x) in terms of sin

\frac{ \sin(x) \frac{1}{ \sin(x) } }{ \cot(x) }

cot(x)

sin(x)

sin(x)

1

Multiply the numerator. Notice that the factors in the numerator are reciprocal so they will factor out to 1.

\frac{1}{ \cot(x) }

cot(x)

1

Notice that cotangent and tan are reciprocal so

\tan(x) = \tan(x)tan(x)=tan(x)

myrzilka [38]3 years ago
3 0

Step-by-step explanation:

\frac{ \sin(x) \csc(x)  }{ \cot(x) }

Rewrite csc(x) in terms of sin

\frac{ \sin(x) \frac{1}{ \sin(x) }  }{ \cot(x) }

Multiply the numerator. Notice that the factors in the numerator are reciprocal so they will factor out to 1.

\frac{1}{ \cot(x) }

Notice that cotangent and tan are reciprocal so

\tan(x)  =  \tan(x)

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The answer is D, x=3
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3 years ago
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A set of raw paired sample data is given below. Convert this raw data into paired ranks, and calculate the value of the rs test
SOVA2 [1]

here is the data set for the complete question

x: 18 21 19 21 20 21

y; 2 14 5 6 18 18

Answer:

B. 0.652

Step-by-step explanation:

x   y   rank of x     rank of y   d         d²

18   2     1                1               0          0

21   14    4                4             0          0

19    5     2               2             0          0

21    6     4               3            1            1

20    18    3             5.5         -2.5      6.25

21     18    4             5.5          -1.5       2.25

∑d² = 8.5

rs = 1 - 6[∑di² + ∑m(m²-1)]/n(n²-1)

= 1 - 6[8.5 +{3(3²-10/12 + 2(2² - 1)/12}]/6(6²-1)

= 1 - 0.348

= 0.652

therefore option b is the right answer.

5 0
3 years ago
the point of M ( a, 4 ) is the midpoint of the line segment with endpoint at A(1,3) and B(5,b). Find the value of a and b
vazorg [7]

The value of a and b from the coordinates are 3 and 5 respectively

<h3>Midpoint of coordinates</h3>

The formula for finding the midpoint of two coordinates is expressed as;

M(x, y) = {x1+x2/2, y1+y1/2}

Given the following coordinates

M(a, 4)

A(1,3)

B(5,b)

Using the formula

a = 1+5/2

a = 6/2

a = 3

Similarly

4 = 3+b/2

8 = 3+b

b = 8-3

b = 5

Hence the value of a and b from the coordinates are 3 and 5 respectively

Learn more on midpoint here: brainly.com/question/18315903

#SPJ1

6 0
2 years ago
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<img src="https://tex.z-dn.net/?f=3%5E%7B3%7D%20%2B%206%282%20%2B%20%5Cfrac%7B3%7D%7B6%7D%20%29" id="TexFormula1" title="3^{3} +
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Answer:

24

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8 0
3 years ago
If x and y in the equations
Brums [2.3K]
We can let
   a = 1/(x-1)
   b = 1/(y+2)
and rewrite the equations as
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   a + 3b = -9
Using the first to write an expression for b, we get
   b = 2a - 10
Substituting this into the second equation gives
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   7a -30 = -9 . . . . . . . . simplify
   7a = 21 . . . . . . . . . . .add 30
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   b = 2·3 - 10 = -4

Now, we can find x and y.
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    x - 1 = 1/3
    x = 1 1/3 = 4/3

    -4 = 1/(y +2)
    y +2 = -1/4
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Then the desired sum is
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    x + y = -11/12

The appropriate choice is ..
   c. -11/12
5 0
3 years ago
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