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Bumek [7]
4 years ago
5

What does the monster say when introduced

Mathematics
1 answer:
mixas84 [53]4 years ago
4 0
I'm guessing "Franken Berry Fanatic Starry" like the cereal. That's what my research tells me.

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If ZMK APY, m M = 112 ° , m Y = 41 ° , m K = (13x 37) ° , and m A = (2y + 7) ° , find the values of x and y.
Lunna [17]

Answer

13x-37=112

13x =149

X=11.4

2y+7=41

Y=24

5 0
3 years ago
Read 2 more answers
The mean volume for a bottle of cologne is 4 ounces and the standard deviation is 0.22 ounces. A random sample of 121 bottles is
adelina 88 [10]

Answer:

The standard error of the mean is 0.02

Step-by-step explanation:

Here, we want to calculate the standard error of the mean.

Mathematically;

standard error of mean = SD/ √n

where SD is the standard deviation and n is the number of samples

From the question, SD = 0.22 and n = 121

Inserting this into the equation

Standard error of the mean = 0.22/√121

= 0.22/11 = 0.02

6 0
3 years ago
• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando
antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:  

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$ Z =  \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}  $

$ Z =  \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}  $

$ Z =  \frac{- 0.09}{ 0.048989 }  $

Z = - 1.84

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p >  α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0
3 years ago
Please help me!!!!!!!! :)​
nirvana33 [79]

Answer:

Step-by-step explanation:

the 30 year olds are more likely to pick chocolate as their favorite ice cream because the fraction of people who like chocolate is 14/20 where the other 3 are 4/20 and 2/20. this can be converted into percentages as well by multipling by 5. 70% of people who are in their 30s like chocolate opposed to the 20% and 10%.

3 0
4 years ago
A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.
PtichkaEL [24]
Answer: The answer is A

Step-by-step explanation: 4c+6a<120 and 4c+4a<100
7 0
3 years ago
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