Circumference of a circle is 2(pi)(r)
2(3.14)(7)= 43.96
So the answer is B
For this case we have to:
x: Let the variable representing the number of people to travel in the group
y: Let the variable representing the number of miles traveled.
If friends only have $22 then we have the following inequality:
![2.50x + 0.75y \leq22](https://tex.z-dn.net/?f=2.50x%20%2B%200.75y%20%5Cleq22)
Now, if there are three people in the group we have that ![x = 3.](https://tex.z-dn.net/?f=x%20%3D%203.)
![2.50 (3) + 0.75y \leq22\\7.5 + 0.75y \leq22\\0.75y \leq22-7.5\\0.75y \leq14.5\\y\leq \frac {14.5} {0.75}\\y\leq19.33](https://tex.z-dn.net/?f=2.50%20%283%29%20%2B%200.75y%20%5Cleq22%5C%5C7.5%20%2B%200.75y%20%5Cleq22%5C%5C0.75y%20%5Cleq22-7.5%5C%5C0.75y%20%5Cleq14.5%5C%5Cy%5Cleq%20%5Cfrac%20%7B14.5%7D%20%7B0.75%7D%5C%5Cy%5Cleq19.33)
The taxi can travel a maximum of 19.33 miles.
On the other hand, if the group wants to travel 10 miles then we have to y = 10.
![2.50x + 0.75 (10) \leq22\\2.50x + 7.5 \leq22\\2.50x \leq22-7.5\\2.50x \leq14.5\\x\leq \frac {14.5} {2.50}\\x \leq5.8](https://tex.z-dn.net/?f=2.50x%20%2B%200.75%20%2810%29%20%5Cleq22%5C%5C2.50x%20%2B%207.5%20%5Cleq22%5C%5C2.50x%20%5Cleq22-7.5%5C%5C2.50x%20%5Cleq14.5%5C%5Cx%5Cleq%20%5Cfrac%20%7B14.5%7D%20%7B2.50%7D%5C%5Cx%20%5Cleq5.8)
Thus, they could travel a maximum of 5 people.
ANswer:
![2.50x + 0.75y \leq22](https://tex.z-dn.net/?f=2.50x%20%2B%200.75y%20%5Cleq22)
Traveling 3 people, the taxi can travel a maximum of 19.33 miles
Traveling 10 miles, a maximum of 5 people can travel
I got x=-4 for the answer
This answer would be 21 because you’d just do 15 increased by 40% which gave me 21