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katrin2010 [14]
3 years ago
10

Solve by elimination: 4x + 4y = 4

Mathematics
1 answer:
ra1l [238]3 years ago
7 0

Answer:

x=−y+1

Step-by-step explanation:

Let's solve for x.

4x+4y=4

Step 1: Add -4y to both sides.

4x+4y+−4y=4+−4y

4x=−4y+4

Step 2: Divide both sides by 4.

<u>4x      </u>  =    <u>−4y+4</u>

4          =        4

x=−y+1

Hope this helps ~

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Step-by-step explanation:

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3 years ago
there are 350 students in the 7th grade class in 1/5 of them play sports. how how many students play sports?​
larisa86 [58]

Answer:

70

Step-by-step explanation:

so divide 350 into 5 groups, which equals 70.

70*5 is 350, so we didn't make a mistake.

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4 0
4 years ago
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Determine whether PQ and UV are parallel,
lys-0071 [83]

Answer:

The answer is below

Step-by-step explanation:

The slope of a line (m) is given by:

m=\frac{y_2-y_1}{x_2-x_1}

Two lines are parallel if they have the same slope and perpendicular if the product of their slope is -1.

1)

Slope\ of\ PQ=\frac{1-(-2)}{9-(-3)}=\frac{1}{4}  \\\\Slope\ of\ UV=\frac{-2-6}{5-3}=-4

Since the product of their slope is -1, they are perpendicular

2)

Slope\ of\ PQ=\frac{1-7}{2-(-10)}=-\frac{1}{2}  \\\\Slope\ of\ UV=\frac{1-0}{6-4}=\frac{1}{2}

Since the slope is not the same or product of their slope is not -1, they are neither parallel or perpendicular

3)

Slope\ of\ PQ=\frac{8-1}{9-1}=\frac{7}{8}  \\\\Slope\ of\ UV=\frac{8-1}{2-(-6)}=\frac{7}{8}

Since the slopes are the same, they are parallel

4)

Slope\ of\ PQ=\frac{3-0}{9-(-4)}=\frac{3}{4}  \\\\Slope\ of\ UV=\frac{6-(-3)}{8-(-4)}=\frac{3}{4}

Since the slopes are the same, they are parallel

5)

Slope\ of\ PQ=\frac{1-2}{0-(-9)}=-\frac{1}{9}  \\\\Slope\ of\ UV=\frac{-1-8}{-2-(-1)}=9

Since the product of their slope is -1, they are perpendicular

6 0
3 years ago
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PIT_PIT [208]

Answer: D

Step-by-step explanation:

Look at the exponents first and order them from least to greatest

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3 years ago
The segments shown below could form a triangle.​
Triss [41]

Answer:

False

Step-by-step explanation:

It's been a while since I did this but here we go:

So to find if the triangle lengths are possible, we take the shorter two lengths and we add them.

Those shorter two lengths sum have to be <em>greater</em> than the longest length.

I hope this helps.

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3 years ago
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